Data: Csolution) 4.18 kJ/kg/°C V(solutions) = 100 mL Density (solutions) = 1.0 g/mL Csolutions) 1.0 mol/L Magnesium oxide reaction data: mugo = 1.0 g T₁ = 28°C T₁ = 35 °C AT = °C Magnesium reaction data: mg = 0.5 g T₁ = 28 °C T₁ = 46 °C AT = °C

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Using the lab data, answer the following questions (4, 5 and 6) , please explain process in detail for understanding. 

Thank you!

Data:
C(solution) = 4.18 kJ/kg/°C
V(solutions) = 100 mL
Density (solutions) = 1.0 g/mL
C(solutions) = 1.0 mol/L
Magnesium oxide reaction data:
mMgo = 1.0 g
T₁ = 28°C
T₁ = 35 °C
AT=
°C
Magnesium reaction data:
mMg = 0.5 g
T₁ = 28 °C
T₁ = 46 °C
AT =
°C
Transcribed Image Text:Data: C(solution) = 4.18 kJ/kg/°C V(solutions) = 100 mL Density (solutions) = 1.0 g/mL C(solutions) = 1.0 mol/L Magnesium oxide reaction data: mMgo = 1.0 g T₁ = 28°C T₁ = 35 °C AT= °C Magnesium reaction data: mMg = 0.5 g T₁ = 28 °C T₁ = 46 °C AT = °C
4. Calculate the enthalpy of reaction, in kJ/mol using AH = q/n and fill in the
blanks for each respective reaction.
5. Using the following series of reactions, calculate the heat of formation for
magnesium oxide and the percentage error in the experiment.
AH₁ =
ΔΗ2 =
AH3=
kJ/mol
MgO(s) + 2HCl(aq)
→ MgCl₂(aq) + H₂O(l)
Mg(s) + 2HCl(aq)
MgCl₂(aq) + H₂(g)
H₂(g) + ¹/2O₂(g)
H₂O(l)
The heat of formation reaction for magnesium oxide is
Mg(s) + 1/2O2(g) → MgO(s)
6. Identify the experimental errors that would be a part of this experiment. Name
at least two and state their effects on the calculations.
kJ/mol
= -285.8 kJ/mol
Transcribed Image Text:4. Calculate the enthalpy of reaction, in kJ/mol using AH = q/n and fill in the blanks for each respective reaction. 5. Using the following series of reactions, calculate the heat of formation for magnesium oxide and the percentage error in the experiment. AH₁ = ΔΗ2 = AH3= kJ/mol MgO(s) + 2HCl(aq) → MgCl₂(aq) + H₂O(l) Mg(s) + 2HCl(aq) MgCl₂(aq) + H₂(g) H₂(g) + ¹/2O₂(g) H₂O(l) The heat of formation reaction for magnesium oxide is Mg(s) + 1/2O2(g) → MgO(s) 6. Identify the experimental errors that would be a part of this experiment. Name at least two and state their effects on the calculations. kJ/mol = -285.8 kJ/mol
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