d(ahmed, samy). true. ?- is_friend(samy, ahmed). true. Note: In the knowledge base, we have only one relation for Ahmed and Samy. example 2  Get the list of all friends of a given person. Examples:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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by using Prolog  <list , backtracking , recursion> ,,, Implement "is_friend" which makes the "friend" relation a symmetric relation

(i.e., if X is friends with Y then Y is friends with X).


Examples:
?- is_friend(ahmed, samy).
true.
?- is_friend(samy, ahmed).
true.
Note: In the knowledge base, we have only one relation for Ahmed and Samy.


example 2 


Get the list of all friends of a given person.
Examples:
?- friendList(ahmed, L).
L = [samy, fouad].
?- friendList(huda, L).
L = [mariam, aisha, lamia].


example 3 


Get the number of friends of a given person. (For the "count" rule, use tail recursion)
Examples:
?- friendListCount(ahmed, N).
N = 2.
?- friendListCount(huda, N).
N = 3.


example 4  :


Suggest possible friends to a person if they have at least one friend in common (at
least one mutual friend). Make sure that the suggested friend is not already a friend of
the person.
Examples:
?- peopleYouMayKnow(ahmed, X).
X = mohammed;
X = said;

?- peopleYouMayKnow(huda, X).
X = hagar;
X = zainab;
X = hend;
X = zainab;

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