DA bacteria Culture that exhibts exponential double in size growth in 10 days. ㅋ Find the growth Constant

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Sample:**

**Growth Function Formula**

\[ P(t) = P_0 e^{kt} \]

- \( P(t) \) represents the population at time \( t \).
- \( P_0 \) indicates the initial value of the population.
- \( k \) is the constant growth rate.
- \( t \) denotes time.

This formula is commonly used to model exponential growth, such as population or investment growth over time. The exponential term \( e^{kt} \) reflects how the quantity grows at a rate proportional to its current value, illustrating the continuous and constant percentage growth.
Transcribed Image Text:**Sample:** **Growth Function Formula** \[ P(t) = P_0 e^{kt} \] - \( P(t) \) represents the population at time \( t \). - \( P_0 \) indicates the initial value of the population. - \( k \) is the constant growth rate. - \( t \) denotes time. This formula is commonly used to model exponential growth, such as population or investment growth over time. The exponential term \( e^{kt} \) reflects how the quantity grows at a rate proportional to its current value, illustrating the continuous and constant percentage growth.
### Exponential Bacterial Growth Problem

**Problem Statement:**
A bacteria culture that exhibits exponential growth doubles in size in 10 days.

**Objective:**
Find the growth constant.

---

### Solution Guide:

1. **Understanding the Problem:**
   - Exponential growth can be represented by the equation:
     \[
     N(t) = N_0 e^{kt}
     \]
     where:
     - \(N(t)\) is the population at time \(t\),
     - \(N_0\) is the initial population,
     - \(k\) is the growth constant,
     - \(t\) is time.
   
2. **Given Information:**
   - The bacteria culture doubles in size in 10 days.
     - If \(N_0\) is the initial population, then after 10 days (\(t=10\)):
       \[
       N(10) = 2N_0
       \]

3. **Setting Up the Equation:**
   \[
   2N_0 = N_0 e^{k \cdot 10}
   \]

4. **Solving for the Growth Constant (\(k\)):**
   - Divide both sides of the equation by \(N_0\):
     \[
     2 = e^{10k}
     \]
   - Take the natural logarithm of both sides:
     \[
     \ln(2) = 10k
     \]
   - Isolate \(k\):
     \[
     k = \frac{\ln(2)}{10}
     \]

5. **Answer:**
   - The growth constant \(k\) is:
     \[
     k = \frac{\ln(2)}{10} \approx 0.0693
     \]

By solving the provided problem in this manner, you can determine the exponential growth constant for the bacteria culture based on the given information.
Transcribed Image Text:### Exponential Bacterial Growth Problem **Problem Statement:** A bacteria culture that exhibits exponential growth doubles in size in 10 days. **Objective:** Find the growth constant. --- ### Solution Guide: 1. **Understanding the Problem:** - Exponential growth can be represented by the equation: \[ N(t) = N_0 e^{kt} \] where: - \(N(t)\) is the population at time \(t\), - \(N_0\) is the initial population, - \(k\) is the growth constant, - \(t\) is time. 2. **Given Information:** - The bacteria culture doubles in size in 10 days. - If \(N_0\) is the initial population, then after 10 days (\(t=10\)): \[ N(10) = 2N_0 \] 3. **Setting Up the Equation:** \[ 2N_0 = N_0 e^{k \cdot 10} \] 4. **Solving for the Growth Constant (\(k\)):** - Divide both sides of the equation by \(N_0\): \[ 2 = e^{10k} \] - Take the natural logarithm of both sides: \[ \ln(2) = 10k \] - Isolate \(k\): \[ k = \frac{\ln(2)}{10} \] 5. **Answer:** - The growth constant \(k\) is: \[ k = \frac{\ln(2)}{10} \approx 0.0693 \] By solving the provided problem in this manner, you can determine the exponential growth constant for the bacteria culture based on the given information.
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