Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
What is the solubility of La(IO₃)₃ in a solution that contains 0.500 M IO₃⁻ ions? (Ksp of La(IO₃)₃ is 7.5 × 10⁻¹²)
**Explanation:**
In this problem, we are asked to find the solubility of lanthanum iodate, La(IO₃)₃, in a solution that already contains a concentration of iodate ions (IO₃⁻) at 0.500 M. The solubility product constant (Ksp) for La(IO₃)₃ is given as 7.5 × 10⁻¹².
**Conceptual Approach:**
To solve this, we apply the concept of solubility product equilibrium and use the given Ksp value.
- Firstly, we write the chemical equation for the dissociation of La(IO₃)₃ in water:
La(IO₃)₃ (s) ⇌ La³⁺ (aq) + 3 IO₃⁻ (aq)
- The expression for the solubility product (Ksp) is:
Ksp = [La³⁺][IO₃⁻]³
Given that the initial concentration of IO₃⁻ is 0.500 M, we will incorporate this into the Ksp expression to find the solubility of La³⁺ in the solution.
The terms will be adjusted according to the stoichiometry of the reaction and the concentration changes during the dissolution process.
**Note:**
This problem involves the common ion effect, where the presence of a common ion (IO₃⁻ in this case) affects the solubility of the compound.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeef920a-b7fc-42c4-a405-16f92aebf3b1%2F873464f4-3672-4271-acd7-249e5b311d32%2F1bqizcq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What is the solubility of La(IO₃)₃ in a solution that contains 0.500 M IO₃⁻ ions? (Ksp of La(IO₃)₃ is 7.5 × 10⁻¹²)
**Explanation:**
In this problem, we are asked to find the solubility of lanthanum iodate, La(IO₃)₃, in a solution that already contains a concentration of iodate ions (IO₃⁻) at 0.500 M. The solubility product constant (Ksp) for La(IO₃)₃ is given as 7.5 × 10⁻¹².
**Conceptual Approach:**
To solve this, we apply the concept of solubility product equilibrium and use the given Ksp value.
- Firstly, we write the chemical equation for the dissociation of La(IO₃)₃ in water:
La(IO₃)₃ (s) ⇌ La³⁺ (aq) + 3 IO₃⁻ (aq)
- The expression for the solubility product (Ksp) is:
Ksp = [La³⁺][IO₃⁻]³
Given that the initial concentration of IO₃⁻ is 0.500 M, we will incorporate this into the Ksp expression to find the solubility of La³⁺ in the solution.
The terms will be adjusted according to the stoichiometry of the reaction and the concentration changes during the dissolution process.
**Note:**
This problem involves the common ion effect, where the presence of a common ion (IO₃⁻ in this case) affects the solubility of the compound.
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