d. VCE = Blank 4 V; %3D e. VC = Blank 5 V ; %3D f. re' = Blank 6 ohms ; %3D
d. VCE = Blank 4 V; %3D e. VC = Blank 5 V ; %3D f. re' = Blank 6 ohms ; %3D
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
The value of VB can be calculated as:
VB=Vth=2.512 V
(b)
The value of VE can be calculated as:
VBE=VB-VEVE=VB-VBEhere,VBE=0.7 VThen,VE=2.512-0.7VE=1.812 V
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Step 6
(c)
Applying KVL in the input loop 1 of Thevenin equivalent circuit:
VB-IBRth-VBE-IERE=0VB-IBRth-VBE-1+βdcRE=0IB=VB-VBERth+1+βdcRESubstituting all the values:IB=2.512-0.75.743×103+1+135×1×103IB=0.012 mA
Therefore, the value of current IE can be calculated as:
IE=1+βdc×IBIE=1+135×0.012×10-3IE=1.632 mA
ANSWER LETTER D TO F
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