Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![6. Find the general solution of (cos cos y +ycos x ) dx+ (sin sin x – x sinsin y ) dy = 0
A. x cos y + y sin x = C
B. - x cos y + y sin x = C
x cos y - y sin x = C
- x cos y - y sin x = C
C.
D.
7. Find the general solution of (vey – 2y³) dr + (xe" – 6xy2 – 2y) dy = 0
A. e*Y + 2xy - y? = C
B. ey - 2xy - y² = C
C.
e*y + 2xy + y? = C
D. ey - 2xy + y? = C
8. Find the general solution of (x²+y² + 1) dx+ (x² – 2xy) dy = 0
A. x? - y? - xy - 1 = Cx
В. х? + у? - ху - 1 %3D Сх
С. х + y? + ху - 1 %3D Сх
D. x? - у? + ху — 1 %3D Сх
9. Find the general solution of (2xy - y? +y) dx+ (3x? – 4xy + 3x) dy = 0
А. х?у? (х - у + 1) %3D С
В. ху(x - у + 1) 3D с
С. ху?(х - у + 1) - с
D. xy?(x - у+ 1) %3D С
10. Find the general solution of (2y) dx+ (x – x³y³) dy = 0.
A. x*y³ - 2 = Cx³y
B. x²y + 2 = Cx°y
C. x'y + 2 = Cx³y
D. x²y° - 2 = Cx³y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5ae5fd6-e751-4c21-bbaf-cf168a06f5be%2F4e8e7a8f-1282-4919-ac58-b9acfbcda256%2Fcq5qoqj_processed.png&w=3840&q=75)
Transcribed Image Text:6. Find the general solution of (cos cos y +ycos x ) dx+ (sin sin x – x sinsin y ) dy = 0
A. x cos y + y sin x = C
B. - x cos y + y sin x = C
x cos y - y sin x = C
- x cos y - y sin x = C
C.
D.
7. Find the general solution of (vey – 2y³) dr + (xe" – 6xy2 – 2y) dy = 0
A. e*Y + 2xy - y? = C
B. ey - 2xy - y² = C
C.
e*y + 2xy + y? = C
D. ey - 2xy + y? = C
8. Find the general solution of (x²+y² + 1) dx+ (x² – 2xy) dy = 0
A. x? - y? - xy - 1 = Cx
В. х? + у? - ху - 1 %3D Сх
С. х + y? + ху - 1 %3D Сх
D. x? - у? + ху — 1 %3D Сх
9. Find the general solution of (2xy - y? +y) dx+ (3x? – 4xy + 3x) dy = 0
А. х?у? (х - у + 1) %3D С
В. ху(x - у + 1) 3D с
С. ху?(х - у + 1) - с
D. xy?(x - у+ 1) %3D С
10. Find the general solution of (2y) dx+ (x – x³y³) dy = 0.
A. x*y³ - 2 = Cx³y
B. x²y + 2 = Cx°y
C. x'y + 2 = Cx³y
D. x²y° - 2 = Cx³y
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