d. e. f. 1 R, Re 1 1 + 4.5×10²2 9.4×10² (1.7×10³ J)-(3.3 × 10² J) (1.7×10³J) = - e= (1.33) sin 25.0° = (1.50) sin I Rp= 0=

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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Physics and Mathematics Exercises

#### Problem d.
Calculate the total resistance \(R_p\) of two resistors in parallel.

\[ 
\frac{1}{R_p} = \frac{1}{4.5 \times 10^2 \, \Omega} + \frac{1}{9.4 \times 10^2 \, \Omega}
\]

So the equation to solve for \( R_p \) is

\[ 
R_p = 
\]


#### Problem e.
Determine the efficiency \( e \) of a system given by the equation:

\[ 
e = \frac{(1.7 \times 10^3 \, J) - (3.3 \times 10^2 \, J)}{(1.7 \times 10^3 \, J)}
\]

Simplify the expression to find the efficiency \( e \).

\[ 
e = 
\]
 

#### Problem f.
Solve for the angle \( \theta \) using the equations for sine:

\[ 
(1.33) \sin 25.0^\circ = (1.50) \sin \theta
\]

Rearrange and solve for \( \theta \):

\[ 
\theta = 
\]
Transcribed Image Text:### Physics and Mathematics Exercises #### Problem d. Calculate the total resistance \(R_p\) of two resistors in parallel. \[ \frac{1}{R_p} = \frac{1}{4.5 \times 10^2 \, \Omega} + \frac{1}{9.4 \times 10^2 \, \Omega} \] So the equation to solve for \( R_p \) is \[ R_p = \] #### Problem e. Determine the efficiency \( e \) of a system given by the equation: \[ e = \frac{(1.7 \times 10^3 \, J) - (3.3 \times 10^2 \, J)}{(1.7 \times 10^3 \, J)} \] Simplify the expression to find the efficiency \( e \). \[ e = \] #### Problem f. Solve for the angle \( \theta \) using the equations for sine: \[ (1.33) \sin 25.0^\circ = (1.50) \sin \theta \] Rearrange and solve for \( \theta \): \[ \theta = \]
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