d. Consider the diagram to the right, with V, = 2.6V, K = 0.55mA/V2, V= 4V, IVJ = 0.8V, and R = 2.4k2. V,=[ mode = e. Now, use V, = 2.1V, K = 0.48mA/v?, v, = 0.88V, IV, = 0.7V, and R = 1.2k2. V,=[ V=[ mode = R f. Finally, use V, = 3.8V, K = 0.45mA/V?, Vc =0.54V, IV, = 0.6V, and R = 2.5k2. VD Vs=| mode =
d. Consider the diagram to the right, with V, = 2.6V, K = 0.55mA/V2, V= 4V, IVJ = 0.8V, and R = 2.4k2. V,=[ mode = e. Now, use V, = 2.1V, K = 0.48mA/v?, v, = 0.88V, IV, = 0.7V, and R = 1.2k2. V,=[ V=[ mode = R f. Finally, use V, = 3.8V, K = 0.45mA/V?, Vc =0.54V, IV, = 0.6V, and R = 2.5k2. VD Vs=| mode =
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Parts D-F please show work, thank you :)
Transcribed Image Text:There are six parts. Use the first circuit diagram for the first three parts and the second circuit diagram for the last three parts. In each case, determine the mode (cutoff "C", saturation "S", or triode "T"), then compute the values of V, Vez and i.
D' 'S'
a. Consider the diagram to the right, with V, = 2.2V, K = 0.5mA/V², Vc =3V, IV,l = 0.6V, and R = 3.2k2.
G
1
mode =
VD
i =
R
b. Now, use V, = 2.7V, K = 0.48MA/V², V = 0.84V, IV,I = 0.8V, and R= 2.4k2.
mode =
VD=
Vs=|
i =
VG
c. Finally, use V, = 3.8V, K = 0.45mA/V², V = 4V, IV, = 0.7V, and R= 1.5k2.
mode =
VD
Vs=|
i =
d. Consider the diagram to the right, with V, = 2.6V, K = 0.55mA/V², V.=4V, IV,J = 0.8V, and R = 2.4k.
V,
G
mode =
VD
i =
%3D
e. Now, use V, = 2.1V, K = 0.48mA/v², Vc= 0.88V, IV,l = 0.7V, and R =1.2k2.
VG
mode =
V
i =
f. Finally, use V, = 3.8V, K = 0.45mA/V², V = 0.54V, IV, = 0.6V, and R = 2.5k2.
mode =
VD=
Vs
i =
To
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