D. B Arr -SA 4 -3 (a) Is there a value x, for -1 ≤ x ≤ 4, such that g(x) = 0? Justify your answer. of 4 + √²₁ 8(+)dt = 4 + [0=0] = 4 4 f(x) The figure above shows the graph of the continuous function f. The regions A, B, C, and D have areas 4, 13, 16, and 3, respectively. For -6 ≤ x ≤ 6, the function g is defined by g(x) = 4 + f2₁f(t) dt. (b) Find the absolute minimum value of g on the interval -6 ≤ x ≤ 6. g'changes sign (- > +) g₁ = g(t) g(x) = f (c) Find the value of ¹ f(5-x) dx 11 there is no value of x for glx) = C absolute minimum at x = 1. since f(x) changes sign (-)
D. B Arr -SA 4 -3 (a) Is there a value x, for -1 ≤ x ≤ 4, such that g(x) = 0? Justify your answer. of 4 + √²₁ 8(+)dt = 4 + [0=0] = 4 4 f(x) The figure above shows the graph of the continuous function f. The regions A, B, C, and D have areas 4, 13, 16, and 3, respectively. For -6 ≤ x ≤ 6, the function g is defined by g(x) = 4 + f2₁f(t) dt. (b) Find the absolute minimum value of g on the interval -6 ≤ x ≤ 6. g'changes sign (- > +) g₁ = g(t) g(x) = f (c) Find the value of ¹ f(5-x) dx 11 there is no value of x for glx) = C absolute minimum at x = 1. since f(x) changes sign (-)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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