2. CREATININE LEVEL PROBLEMTo compare the performance of the two machines a technician took eight specimens ofblood and measured the creatinine level (in micromoles per litre) of each specimenusing each machine. The results were as follows.SpecimAnalyzerAnalyzer 10enAB9611133نياev2Test Procedure:17150301083499p-value:Conclusion: At alpha= 0.05,955Justify your choice of test procedure:77691361212784848The data can also be found in the worksheet "creatinine_level" of excel file"exer3_data.xlsx". R outputs can be found in the file "exer3_outputs.pdf".Let difference be Analyzer A-Analyzer B.73d. A point estimate of the average difference in the creatinine level (inmicromoles per litre) of each specimen using each machine is67e. At 5% level of significance, test if there is difference in the measuredcreatinine level (in micromoles per litre) of each specimen using eachmachine.Ho: (in symbols): (in words) The average creatinine level (in micromolesper litre) of the specimen using Analyzer A isthe averagecreatinine level (in micromoles per litre) of the specimen using Analyzer A.Ha: (in symbols)___________ (in words) The average creatinine level (in micromolesper litre) of the specimen using Analyzer A isthe averagecreatinine level (in micromoles per litre) of the specimen using Analyzer B. 2. CREATININE LEVEL PROBLEMSome statisticsAnalyzer A: mean = 105.75; median = 99.5Analyzer B: mean = 97.5; median = 89.5Let difference = Analyzer A - Analyzer Bd=8.25Md = 7data: Analyzer AW = 0.88028p-value = 0.1895Wilk-Shapiro Test for Normalitydata: Analyzer BW = 0.91541p-value = 0.3937Ha: not equal to 0t = 2.9652p-value = 0.02095data: differenceW = 0.95788p-value 0.7897Student's t-test on Paired Samples: Analyzer A vs Analyzer BHa: less than 0t = 2.9652p-value = 0.9895Ha: greater than 0t = 2.9652p-value = 0.01048Wilcoxon Matched-Pairs Signed Ranks Test: Analyzer A vs Analyzer BHa: not equal to 0Ha: less than 0Ha: greater than 0V = 27V = 27V = 27p-value = 0.03461p-value = 0.9888p-value0.01731F-test for Equality of VariancesF = 1.1311p-value = 0.856Student's t-test on Two Independent Pop'n Means: Analyzer A vs Analyzer BHa: not equal to 0Ha: less than 0.Ha: greater than 0t = 9.2109t = 9.2109t = 9.2109p-value 0.00003668 p-value=1p-value = 0.00001834Welch's t-test on Two Independent Pop'n Means: Analyzer A vs Analyzer BHa: not equal to 0Ha: less than 0Ha: greater than 0t = 9.4637t = 9.4637t = 9.4637p-value = 1p-value = 0.00003073p-value = 0.00001537Mann-Whitney Test on Two Independent Pop'n Means: Analyzer A vs Analyzer BHa: not equal to 0.Ha: greater than 0Ha: less than 0W = 36W = 36W = 36p-value = 0.01427p-value = 0.9952p-value0.007133

The problem is to test if there is a difference in the measured creatinine level b/w the two…

Answered: d. A point estimate of the average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose the lengths of human pregnancies are normally distributed with μ = 266 days and o 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with μ=266 days and o=16 days. The area to the left of X=230 is 0.0122. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last less than 230 days is 0.0122 OB. The proportion of human pregnancies that last more than days is C Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) ⒸA. The probability that a randomly selected human pregnancy lasts less than OB. The probability that a randomly selected human pregnancy lasts more than days is days is A 230 268 Q
Can balloons hold more air or more water before bursting? A student purchased a large bag of 12-inch balloons. He randomly selected 10 balloons from the bag and then randomly assigned half of them to be filled with air until bursting and the other half to be filled with water until bursting. He used devices to measure the amount of air and water was dispensed until the balloons burst. Here are the data
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Suppose the lengths of human pregnancies are normally distributed with µ= 266 days ando = 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with u = 266 days and o = 16 days. The area to the left of X= 250 is 0.1587. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The proportion of human pregnancies that last less than days is O B. The proportion of human pregnancies that last more than days is 250 266 Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts more than days is O B. The probability that a randomly selected human pregnancy lasts less than days is (b) The…

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d. A point estimate of the average difference in the creatinine level (in micromoles per litre) of each specimen using each machine is e. At 5% level of significance, test if there is difference in the measured creatinine level (in micromoles per litre) of each specimen using each machine.