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D. 22√2) 3 2√3) 9. if f(x) is even function and g(x) is odd function then a. 18 b. 24 (f(x) g(x) + 4) dx = c. 12 d. 0

D. 22√2) 3 2√3) 9. if f(x) is even function and g(x) is odd function then a. 18 b. 24 (f(x) g(x) + 4) dx = c. 12 d. 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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pleasssse solve questionnnnnn  9 and 10 please sir 

4. The inverse function of y=x²-2x+2 is - ƒ^²(x)=-1+√x-1 c. f¹(x) = −1+√√√x-1 5. cos`¹ (cos ³) = a. 6. lim бя 5 a.-3 == x+1 a. 0 √√3x² +1 8. If y=x√ then y' (4) = (2) + 2√2 a. 2 a. 2√2 x2-1 +21 7. If y ==—ƒ(x²), ƒ' (4) = 3, ƒ(4) = 12, then y' (2) = a. √3-1 b. 4 бл b. 6,707 7 b. 3 3 (+) 2√3 9. if f(x) is even function and g(x) is odd function then ](/(x).g(x) + 4) dx = a. 18 b. 24 c. 12 b. 33 b. 0 b. f¹(x)=-1-√√x-1 d. ƒ^¯¹(x)=1+√√x−1 x21 c c.-√3 b. 1 c. 3 c. 8+4ln4 10. if In x³ = 6log2-3log 4 then x = a. e² c. 1 11. The slope of the tangent line to the curve xe +3 x² = y² + 8x-1 at (1, 0) = b.-2 c. 12 12. The value of c that satisfy the mean value theorem for f(x) = C. c. √3 d. 1 x-1 x5-1 d. √3 d. 2 ut d. - 1 -on [-2, 0] is d. 0 d. e d.-√3 +1
Transcribed Image Text:4. The inverse function of y=x²-2x+2 is - ƒ^²(x)=-1+√x-1 c. f¹(x) = −1+√√√x-1 5. cos`¹ (cos ³) = a. 6. lim бя 5 a.-3 == x+1 a. 0 √√3x² +1 8. If y=x√ then y' (4) = (2) + 2√2 a. 2 a. 2√2 x2-1 +21 7. If y ==—ƒ(x²), ƒ' (4) = 3, ƒ(4) = 12, then y' (2) = a. √3-1 b. 4 бл b. 6,707 7 b. 3 3 (+) 2√3 9. if f(x) is even function and g(x) is odd function then ](/(x).g(x) + 4) dx = a. 18 b. 24 c. 12 b. 33 b. 0 b. f¹(x)=-1-√√x-1 d. ƒ^¯¹(x)=1+√√x−1 x21 c c.-√3 b. 1 c. 3 c. 8+4ln4 10. if In x³ = 6log2-3log 4 then x = a. e² c. 1 11. The slope of the tangent line to the curve xe +3 x² = y² + 8x-1 at (1, 0) = b.-2 c. 12 12. The value of c that satisfy the mean value theorem for f(x) = C. c. √3 d. 1 x-1 x5-1 d. √3 d. 2 ut d. - 1 -on [-2, 0] is d. 0 d. e d.-√3 +1
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