Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![The equation presented is as follows:
\[ D \: x^2 - 8x + 8 = -7 \]
This is a quadratic equation where:
- \( D \) is a constant.
- \( x^2 \) is the quadratic term.
- \(-8x\) is the linear term.
- \( 8 \) is a constant term on the left side.
- The equation equals \(-7\).
To solve for \( x \), one would typically rearrange the equation so that all terms are on one side, setting the equation to zero:
\[ D \: x^2 - 8x + 15 = 0 \]
This can then be solved using methods such as factoring, completing the square, or the quadratic formula, depending on the context of \( D \) and the other coefficients.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F363f9d0b-8f44-408c-8460-539c78c52e75%2F222acae4-6c42-4465-a8cb-e8bedabb595e%2F6bh59dg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equation presented is as follows:
\[ D \: x^2 - 8x + 8 = -7 \]
This is a quadratic equation where:
- \( D \) is a constant.
- \( x^2 \) is the quadratic term.
- \(-8x\) is the linear term.
- \( 8 \) is a constant term on the left side.
- The equation equals \(-7\).
To solve for \( x \), one would typically rearrange the equation so that all terms are on one side, setting the equation to zero:
\[ D \: x^2 - 8x + 15 = 0 \]
This can then be solved using methods such as factoring, completing the square, or the quadratic formula, depending on the context of \( D \) and the other coefficients.
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