(d) What is the probability that a random sample of 16 people will exceed the weight limit? An elevator at a college has a posted weight limit of 2,700 pounds, and a maximum capacity of 16 people. We determined that if the sample mean x 2 168.75 for a particular sample of 16 people, then the weight capacity will be exceeded. We are asked to determine the probability that a random sample of 16 people will exceed the weight limit. We previously determined the mean and standard deviation of the sampling distribution of x. H=165 -= 7.75 We are given that the distribution of weights of individuals on campus is approximately normal, so the sampling distribution of x is approximately normal also. We can calculate the desired probability by standardizing. Recall the standardization formula. 20) = P( 22 b=2²) P(x z b) In other words, we need to find the following. (Round your answer to four decimal places.) 7.75 x-1657 = P(22. = P(Z 2 165 = 1-P zs 7.75 P(x 2 168.75) = 7.75 1x

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(d) What is the probability that a random sample of 16 people will exceed the weight limit?
An elevator at a college has a posted weight limit of 2,700 pounds, and a maximum capacity of 16 people. We determined that if the sample mean x ≥ 168.75 for a particular sample of 16 people, then the weight capacity will be exceeded. We are asked to
determine the probability that a random sample of 16 people will exceed the weight limit.
We previously determined the mean and standard deviation of the sampling distribution of x.
We are given that the distribution of weights of individuals on campus is approximately normal, so the sampling distribution of X is approximately normal also. We can calculate the desired probability by standardizing. Recall the standardization formula.
= P( ₂2 b=H=²)
H = 165
σ- = 7.75
P(x ≥ b) = Pzz
In other words, we need to find the following. (Round your answer to four decimal places.)
7.75
X - 165
= P(₂
P(x > 168.75) =
= P(z
=
= 1 -
> 165
≤7.75
7.75
x
X
Transcribed Image Text:(d) What is the probability that a random sample of 16 people will exceed the weight limit? An elevator at a college has a posted weight limit of 2,700 pounds, and a maximum capacity of 16 people. We determined that if the sample mean x ≥ 168.75 for a particular sample of 16 people, then the weight capacity will be exceeded. We are asked to determine the probability that a random sample of 16 people will exceed the weight limit. We previously determined the mean and standard deviation of the sampling distribution of x. We are given that the distribution of weights of individuals on campus is approximately normal, so the sampling distribution of X is approximately normal also. We can calculate the desired probability by standardizing. Recall the standardization formula. = P( ₂2 b=H=²) H = 165 σ- = 7.75 P(x ≥ b) = Pzz In other words, we need to find the following. (Round your answer to four decimal places.) 7.75 X - 165 = P(₂ P(x > 168.75) = = P(z = = 1 - > 165 ≤7.75 7.75 x X
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