(d) What is the difference between the parametrs of overhead line and underground cables?

Introductory Circuit Analysis (13th Edition)
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C and D only Some time ago they solved A and B
A 3-phase, transmission line is to be built using Falcon ACSR conductor with a manugfacture data given in the
attached table. Bundeling is to be used, with three conductors per phase spaced symetrically 30cm apart and a
horizontal tower configuration is used, with a distance of 5m between adjacent phases as shown below.
30cm
-5m
-5m
Assuming that the line is uniformly transposed.
(a) Determine the transmission line inductance per phase in H/km.
(b) Determine the transmission line capacitance per phase in F/km
(c) What is the thermal rating (maximum current carrying capcity) of this transmission line?
(d) What is the difference between the parametrs of overhead line and underground cables?
Given: µ0=4x10-7 H/m, ɛ0=8.854x10-12 F/m, 1 mile=1.607km, 1 meter=3.28 feet, 1 feet=12 inches
Transcribed Image Text:A 3-phase, transmission line is to be built using Falcon ACSR conductor with a manugfacture data given in the attached table. Bundeling is to be used, with three conductors per phase spaced symetrically 30cm apart and a horizontal tower configuration is used, with a distance of 5m between adjacent phases as shown below. 30cm -5m -5m Assuming that the line is uniformly transposed. (a) Determine the transmission line inductance per phase in H/km. (b) Determine the transmission line capacitance per phase in F/km (c) What is the thermal rating (maximum current carrying capcity) of this transmission line? (d) What is the difference between the parametrs of overhead line and underground cables? Given: µ0=4x10-7 H/m, ɛ0=8.854x10-12 F/m, 1 mile=1.607km, 1 meter=3.28 feet, 1 feet=12 inches
Step2
b)
Per phase inductance of the line,
Lph = 2 × 10-7 ln (
GMD
GMR
Lph = 2 × 10−7 In
Lph = 5.45 × 10−7 H/m
Lph = 5.45 × 10¯4 H/km
per phase capacitance of the line
Cn
=
In
2π €0
=
GMD
GMR
GMR,
D₂ = √r•d² [r= 1 m d = 0.3 m]
3
Dε = √√1 × 0. 3² = 0. 448
S
6.299
0.4123
GMD = Deg = √√/Daß · Dâc · Dac
AB
eq
Deg
3/5 × 5 × 10 = 6.299
Cn
2πx8.854×10
6.299
0.448
In
-12
=
DAB
21.04 × 10-⁹ F/km
- 5m DB
-
Transcribed Image Text:Step2 b) Per phase inductance of the line, Lph = 2 × 10-7 ln ( GMD GMR Lph = 2 × 10−7 In Lph = 5.45 × 10−7 H/m Lph = 5.45 × 10¯4 H/km per phase capacitance of the line Cn = In 2π €0 = GMD GMR GMR, D₂ = √r•d² [r= 1 m d = 0.3 m] 3 Dε = √√1 × 0. 3² = 0. 448 S 6.299 0.4123 GMD = Deg = √√/Daß · Dâc · Dac AB eq Deg 3/5 × 5 × 10 = 6.299 Cn 2πx8.854×10 6.299 0.448 In -12 = DAB 21.04 × 10-⁹ F/km - 5m DB -
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