d the thickness of the boundary layer at a distance of x = 20 c

Elements Of Electromagnetics
7th Edition
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Calculate the heat transfer from a 60 cm x 60 cm plate on which air flows at 40⁰C and. The plate temperature is 100⁰ C while the air speed is 5 m/s.Find the thickness of the boundary layer at a distance of x = 20 cm.
#The film temperatore, T:
こ
ニ
+ The poferthes of air at Fic and 1atm: [ufingthe table of proferties
of air]
0.02881W
m.K
1.995X10 Smils
0.7177
# The reynolds nuemb er, Rq: (at he end of the blete)
5mls) C0-6m)
(1.995X10 Spm is)
= 1.50376 x (05 < Sx105(Rex)
→ ReL
VL
: L= Side= 0.6m
%3D
こ
> The flow is laminar.
# The arerage nussetHt number, Nu :
> Nu = hL = 0.664RPel13
0.5
=>
hL = 230.5358
+ The average
- h= (230. 5358 ) (0.02881)
(0.6m)
11.0696 wlm.k
# The heat tsansfer, d:
> d = hAsCTs-To) = (1.0676 )(0.6 x0.6) (100 -40 )= 239.1ow
heat transfer Coefficient, h :
Transcribed Image Text:#The film temperatore, T: こ ニ + The poferthes of air at Fic and 1atm: [ufingthe table of proferties of air] 0.02881W m.K 1.995X10 Smils 0.7177 # The reynolds nuemb er, Rq: (at he end of the blete) 5mls) C0-6m) (1.995X10 Spm is) = 1.50376 x (05 < Sx105(Rex) → ReL VL : L= Side= 0.6m %3D こ > The flow is laminar. # The arerage nussetHt number, Nu : > Nu = hL = 0.664RPel13 0.5 => hL = 230.5358 + The average - h= (230. 5358 ) (0.02881) (0.6m) 11.0696 wlm.k # The heat tsansfer, d: > d = hAsCTs-To) = (1.0676 )(0.6 x0.6) (100 -40 )= 239.1ow heat transfer Coefficient, h :
J= looc
V= Smls
niveni As = 0.6ox0.6om?
1.
Too = 40°C
# The external fooced Convection:
The parallel flow over flat plate is a
foo ced Convection.
example of external
In this Caslry
m
Nu = C R" R"
%3D
and
Recr = Sx1o5
%3D
Ta,r
Aix
A
Ts
Fig: The schemadic
Transcribed Image Text:J= looc V= Smls niveni As = 0.6ox0.6om? 1. Too = 40°C # The external fooced Convection: The parallel flow over flat plate is a foo ced Convection. example of external In this Caslry m Nu = C R" R" %3D and Recr = Sx1o5 %3D Ta,r Aix A Ts Fig: The schemadic
Expert Solution
Step 1

Re @ x =20 cm 

Re = ρ Vxμ = Vxν= 5 *0.21.995 x 10-5=50125.31328 < critical reynold snumber , thus the flow is laminar

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