d) The cell Mg(s) + Cd2(aq) Mg+ + Cd(s) has Ecell=+1.97 V. The magnesium electrode was dipped into a 1.5 M solution of MgSO4 and the cadmium electrode was dipped into a solution of unknown Cd2+ concentration. The potential of the cell was measured and was found to be Ecell = +1.89 V. What was the unknown Cd²t concentration?

d) The cell Mg(s) + Cd2(aq) Mg+ + Cd(s) has Ecell=+1.97 V. The magnesium electrode was dipped into a 1.5 M solution of MgSO4 and the cadmium electrode was dipped into a solution of unknown Cd2+ concentration. The potential of the cell was measured and was found to be Ecell = +1.89 V. What was the unknown Cd²t concentration?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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O O257V
d) The cell Mg(s) + Cd²"(aq) → Mg+ + Cd(s) has E°cell = +1.97 V. The magnesium electrode
was dipped into a 1.5 M solution of MgSO4 and the cadmium electrode was dipped into a
solution of unknown Cd2 concentration. The potential of the cell was measured and was found
to be Ecell =+1.89 V. What was the unknown Cd2+ concentration?
ecell E°cell-
57V InQ
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