Homework Help is Here – Start Your Trial Now!
Engineering
Computer Engineering
d) ShiftRows This step is the same as the ShiftRows step in the AES encryption. Circularly shift the rows in each block in the following fashion: The first row remains the same. Shift the second row one position to the left. Shift the third row two positions to the left. Finally, shift the fourth row three positions to the left. o Example: Input: WVOG JTXQ HUHX ICWY YMGH TRKQ HQPW KYVG LPYS EWGO INTO FORM OAAA AAAA AAAA AAAA Output: WVOG TXQJ HXHU YICW YMGH RKQT PWHQ GKYV LPYS WGOP TOIN MFOP OAAA AAAA AAAA AAAA

d) ShiftRows This step is the same as the ShiftRows step in the AES encryption. Circularly shift the rows in each block in the following fashion: The first row remains the same. Shift the second row one position to the left. Shift the third row two positions to the left. Finally, shift the fourth row three positions to the left. o Example: Input: WVOG JTXQ HUHX ICWY YMGH TRKQ HQPW KYVG LPYS EWGO INTO FORM OAAA AAAA AAAA AAAA Output: WVOG TXQJ HXHU YICW YMGH RKQT PWHQ GKYV LPYS WGOP TOIN MFOP OAAA AAAA AAAA AAAA

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
See similar textbooks
icon
Related questions
Question
Complete both functions in c++.
d) Shift Rows This step is the same as the ShiftRows step in the AES encryption. Circularly shift the rows in each block in the following fashion: The first row remains the same. Shift the second row one position to the left. Shift the third row two positions to the left. Finally, shift the fourth row three positions to the left. Example: Input: WVOG JTXQ HUHX ICWY YMGH TRKQ HQPW KYVG LPYS EWGO INTO FORM OAAA AAAA AAAA AAAA Output: WVOG TXQJ HXHU YICW Input: WVOG TXQJ HXHU YICW YMGH YMGH RKQT PWHQ GKYV RKQT PWHQ GKYV LPYS WGOP LPYS WGOP TOIN MFOP e) Parity Bit Convert each character to its numeric value (0-127) and use the most significant bit as a parity bit. O Example: OAAA AAAA AAAA AAAA The numeric value of 'A' is 6510 = 010000012 = 4116- There is an even number of ones in its binary representation, so the most significant bit stays unchanged. However, the numeric representation of 'C' is 6710 = 010000112. In this case, since there is and odd number of ones (i.e., three) in the binary representation, the most significant bit will be set to one in order to have number of one in the binary representation, i.e., 'C' with added parity will be 110000112 = 19510 = c316- Output (in hexadecimal): d7 56 cf 47 d4 d8 d1 ca 48 d8 48 55 59 c9 c3 d7 59 4d 47 48 d2 4b d1 d4 50 d7 48 dl 47 4b 59 56 cc 50 59 53 d7 47 cf 50
Transcribed Image Text:d) Shift Rows This step is the same as the ShiftRows step in the AES encryption. Circularly shift the rows in each block in the following fashion: The first row remains the same. Shift the second row one position to the left. Shift the third row two positions to the left. Finally, shift the fourth row three positions to the left. Example: Input: WVOG JTXQ HUHX ICWY YMGH TRKQ HQPW KYVG LPYS EWGO INTO FORM OAAA AAAA AAAA AAAA Output: WVOG TXQJ HXHU YICW Input: WVOG TXQJ HXHU YICW YMGH YMGH RKQT PWHQ GKYV RKQT PWHQ GKYV LPYS WGOP LPYS WGOP TOIN MFOP e) Parity Bit Convert each character to its numeric value (0-127) and use the most significant bit as a parity bit. O Example: OAAA AAAA AAAA AAAA The numeric value of 'A' is 6510 = 010000012 = 4116- There is an even number of ones in its binary representation, so the most significant bit stays unchanged. However, the numeric representation of 'C' is 6710 = 010000112. In this case, since there is and odd number of ones (i.e., three) in the binary representation, the most significant bit will be set to one in order to have number of one in the binary representation, i.e., 'C' with added parity will be 110000112 = 19510 = c316- Output (in hexadecimal): d7 56 cf 47 d4 d8 d1 ca 48 d8 48 55 59 c9 c3 d7 59 4d 47 48 d2 4b d1 d4 50 d7 48 dl 47 4b 59 56 cc 50 59 53 d7 47 cf 50
Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY
SEE MORE TEXTBOOKS