D Question 6 Find the amplitude, period, midline, and horizontal shift of the following function: y = -3 cos(3x – 12) + 2 Amplitude: Period: Midline: Horizontal Shift: units to the Type "pi" if you need to usen in any expressions.

Q: 2x+1=5

A: To solve for x

Q: -2(4-2b)+8b

A: The given expression is -2(4-2b)+8b

Q: 3x + 6 =18

A: To solve for x

Q: 4y-5(3y+10)=16

A: SOLUTION-

Q: -8(3p + 4)=8p

A: Given  -8(3p + 4)=8p  p =?

Q: (Y+12)+28

A: (Y+12)+28

Q: 3x+2=5

A:

Q: 22p+11=4p-7

A: Given: 22p + 11 = 4p - 7…

Q: 2x(7)+7=

A:

Q: 5a +7=10

A: 5a + 7 = 10 Subtract 7 on both side, 5a =3

Q: -12 = 4m + 4

A:

Q: 7x + 8y = 67  3x + 6y = 39

A: Solving system of equations means finding the value of the variable involved into the equation.

Q: 5x+32=-20x+48

A: We will use simple algebra to find the value of x.

Q: x2+9x=-14

A: Given equation is x2+9x=-14 The equation can be solved by splitting the middle term.…

Q: What is the solution of the system in the format (xy) ? "don't add space to ordered pai y = 5x – 12…

A: Given,           y=5x-12           y=-4x+6

Q: y = - x+2x +3

A: Given,            y=-x^2+2x+3

Q: How did you get y= 23x+103

A: The given equation is: 2x-3y=7 We first try to write it in the y=mx+b form to find the slope.…

Q: -3)=-32

A: -8(x-3)=-32 -8x + 24 = -32 -8x = -32-24 -8x = -56

Q: -4y-12=6y+58

A: Given:

Q: 6x2 + 13x = -6

A: We have to solve the quadratic equation.

Q: Find the value of 5C2+4C3+6P1?

A:

Q: 8 + 6r - 2

A: Given,8+6r-2

Q: 2m+8=22 and 4(3n+5)= -28

A:

Q: -5(2t-3)+4t=2t-2

A: Answer is 17/8 Explanation is given below..

Q: y = 10x - 53 2y = -13x +92

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: A In the diagram above mzABE=8x+55 and mZBCE=D7x-25. Find mZDCE

A:

Q: -8d-5d +7d=72

A: Solve for the value of d

Q: 6y²=7y+20

A: Given: 6y2=7y+20

Q: 2x+19=15

A: