D Question 27 To prove 3+7+ 11 + ... + (4n − 1) = n(2n + 1) holds for an arbitrary n € Z*, the Basis Step is to prove Check ALL that apply, i.e. you are allowed to choose ONE or MORE answers. O P(1) : (4-1) = 1(2+1) O P(1) : 3+ (4-1) = 1(2+1) O P(1) : 3 = 1(2+1) P(1) : 3+7 (4-1)+1(2+1)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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D
Question 27
To prove 3+7+ 11 + ... + (4n − 1) = n(2n + 1) holds for an arbitrary n € Z*,
the Basis Step is to prove
Check ALL that apply, i.e. you are allowed to choose ONE or MORE answers.
O P(1) : (4-1) = 1(2+1)
O P(1) : 3+ (4-1) = 1(2+1)
OP(1) :3 = 1(2+1)
P(1) : 3+7 (4-1)+1(2+1)
Transcribed Image Text:D Question 27 To prove 3+7+ 11 + ... + (4n − 1) = n(2n + 1) holds for an arbitrary n € Z*, the Basis Step is to prove Check ALL that apply, i.e. you are allowed to choose ONE or MORE answers. O P(1) : (4-1) = 1(2+1) O P(1) : 3+ (4-1) = 1(2+1) OP(1) :3 = 1(2+1) P(1) : 3+7 (4-1)+1(2+1)
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