d) For the equation N2H4 → NH3 + N2, if the theoretical yield is 28.0 grams of N2, what mass in grams of N2H4, would have to react? by e) For the equation FeS + HCI → FeC2 + H2S, if 35.0g of FeS is added to 35.0g of HCl and allowed to react, what is the theoretical yield of H2S? by f) Using the numbers from problem e) above, if 10.2 g of H2S were obtained in the lab (actual yield), what is the percent yield?
d) For the equation N2H4 → NH3 + N2, if the theoretical yield is 28.0 grams of N2, what mass in grams of N2H4, would have to react? by e) For the equation FeS + HCI → FeC2 + H2S, if 35.0g of FeS is added to 35.0g of HCl and allowed to react, what is the theoretical yield of H2S? by f) Using the numbers from problem e) above, if 10.2 g of H2S were obtained in the lab (actual yield), what is the percent yield?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Chemistry Problems**
**d)** For the equation \( \text{N}_2\text{H}_4 \rightarrow \text{NH}_3 + \text{N}_2 \), if the theoretical yield is 28.0 grams of \( \text{N}_2 \), what mass in grams of \( \text{N}_2\text{H}_4 \) would have to react?
**Answer:** ___________g
---
**e)** For the equation \( \text{FeS} + \text{HCl} \rightarrow \text{FeCl}_2 + \text{H}_2\text{S} \), if 35.0 grams of \( \text{FeS} \) is added to 35.0 grams of \( \text{HCl} \) and allowed to react, what is the theoretical yield of \( \text{H}_2\text{S} \)?
**Answer:** ___________g
---
**f)** Using the numbers from problem **e** above, if 10.2 grams of \( \text{H}_2\text{S} \) were obtained in the lab (actual yield), what is the percent yield?
**Answer:** ___________%
---
**g)** How many grams of \( \text{K}_2\text{C}_2\text{O}_4 \), potassium oxalate, would contain 182 grams of pure potassium?
**Answer:**
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