D At point A, P = 2 atm, V = 0.5 m, and T = 200 K. For each step, use the graph to find W, the work done on the system, by counting the number of squares of area under the graph, and multiplying by the area of cach square. For the curved path in step 2, approximate the area under the curve as best you can, by counting partial squares. Then use the first law of thermodynamics to find AU and Q. Make sure you have the correct sign for each quantity. W AU Step 1: Step 2: Step 3: Step 4: Step 1 A to B Step 2 B to C Step 3 C to D Step 4 D to A

Q: 48. A particle of m moves along x axis under the action of a foce J. Its motion is described by the…

A: F=-2kx3f=-dvdx=2kx3v(x)=2k∫dxx3=-kx2 KE=12mv2=12mdxdt2

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A: Given: v-t diagram

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A: Acceleration due to gravity acts directly downward direction

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Q: B. What is the power radiated from a nude body 1.75m² in the area

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A:

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A: Initial Height H = 4R Initial velocity = 0

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A:

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A:

Q: A projectile is fired with an initial velocity of 400 m/s hits a cliff 2000 meter apart determine…

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Q: 2.21 and 2.22 Drtermite the x and y cmpowits of eacli of the forces shown. 120N 60 Ib 80 N 100N 30…

A: Given, Force vectors in x-y plane.

Q: 2. F = e²i+yj + x²yk, A. y²i2zy2j-e²k B. x²i-2y2j-e²j C. y²i-2z2j-e²k D. z²i2zy2j+e²k E.…

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Q: calipers,

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Q: The kinematic equation of a material point motion has the form x = A + Bt + Ct², where

A: The position of particle is x=A+Bt+Ct^2   =1.7+5.6t+3.1t^2

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A:

Q: 5. A particle of mass M = 102" Kg decays, while at rest, into a particle of mass m = 4x 10-28 %3D Kg…

A: Given a particle of mass M=10-27kg =10×10-28kg decays into a  particle of mass  m=4×10-28kg

Q: 06 what we mean by conservation of angular momentum for system of particle motion?

A: It is asked conservation of angular momentum for system of particle motion:

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Special Relativity

The theory of special relativity discusses how space and time are related to objects traveling along a straight line at a constant speed. Simply stated, as an object reaches the speed of light, its mass becomes infinite and it is unable to move faster than light. This interstellar speed limit has been the topic of much debate in astronomy, and also in science fiction when people consider how to fly over large distances.