We have an electrical circuit whose different elements are connected to an alternating current generator of frequency w, as shown in the figure below Al an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(e) and -qe). and through the coil (self inductance L) passes a known instantaneous current i(t) = sin (wt + m2). Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of the closed surfaces Sa, Sb, and Sc. i(t) + qit) i(t)
We have an electrical circuit whose different elements are connected to an alternating current generator of frequency w, as shown in the figure below Al an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(e) and -qe). and through the coil (self inductance L) passes a known instantaneous current i(t) = sin (wt + m2). Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of the closed surfaces Sa, Sb, and Sc. i(t) + qit) i(t)
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Transcribed Image Text:We have an electrical circuit whose different elements are connected to an alternating current generator of frequency
w, as shown in the figure below.
At an instant t, the plates of the capacitor shown (capacitance C) have equal and opposite charges +q(t) and -q(t).
and through the coil (self inductance L) passes a known instantaneous current i(t) = l sin (wt + T2).
Knowing that the circuit is in its steady state, obtain for time t the electric field as a function of time at each of the
closed surfaces Sa, Sb, and Sc.
i(t)
+ qlt)
S.
qlt)
i(t)
Step by step please
Wrong|answer gives u downvote
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