d According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892
d According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n = 40.5%). In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese? 0.2252 0.2448 0.2661 0.2892
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![Questions 6-8 are related
6
According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n =
40.5%).
In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese?
0.2252
0.2448
0.2661
0.2892
7
8
a
b
9
с
d
a
b
с
d
a
b
с
d
a
b
с
с
d
10
Questions 9-11 are related to the following
To build an interval estimate with a 95% level of confidence for the average weekly wage in Indiana a random sample of
working adults provided the accompanying data (in dollars):
a
b
с
d
11
a
b
с
d
12
a
b
Given = 40.5% and n = 610 above, the fraction of sample proportions that fall within ±0.03 (3 percentage points) from
it is,
с
d
0.7841
0.8254
0.8688
0.9145
Given = 40.5% and n = 610 above, the lower and upper ends of the interval which captures 95 percent of all sample
proportions is,
0.389
0.383
0.376
0.366
1150
1006
1089
1163
936
835
1125
1002
929
1122
892
962
924
736
967
1003
The point estimate of population mean weekly wage is,
929.74
978.67
0.421
0.427
0.434
0.444
1030.18
1084.40
995.99
987.44
960
1045
1163
1052.06
1057.53
1064.37
1072.92
868
1261
1070
1147
1135
851
1368
1175
730
1240
1319
1193
1193
1101
1164
817
1247
810
1187
941
818
878
967
738
844
1218
978
963
957
The interval estimate for the population mean weekly wage with a 95% confidence level is,
1008.30
1002.83
1245
1146
965
1350
1073
1116
1519
733
1170
1042
974
748
766
923
830
873
1204
1117
1149
1490
879
982
865
827
You want to achieve a margin of error of $20 for the 95% confidence interval for the population weekly wage rate. What
is the minimum sample size to obtain this MOE?
For planning value use the standard deviation from original sample.
318
306
294
283
Suppose 280 students are taking E270. Each student is assigned to take a random sample of 100 workers in Indiana and
each build a 95% confidence interval for the average weekly wage.
How many of these 280 intervals should we expect to capture the actual population mean weekly wage.
95
275
270
266](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d91dd73-3131-4b2d-a931-17ff30102265%2F6196b75b-1868-4994-9ad0-7bca458a80d2%2Fdtbtbhx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Questions 6-8 are related
6
According to centers for Disease Control and Prevention, 40.5% of the adult population in the Midwest are obese (n =
40.5%).
In a random sample of 610 Midwestern adults, what is the probability that more than 42% are obese?
0.2252
0.2448
0.2661
0.2892
7
8
a
b
9
с
d
a
b
с
d
a
b
с
d
a
b
с
с
d
10
Questions 9-11 are related to the following
To build an interval estimate with a 95% level of confidence for the average weekly wage in Indiana a random sample of
working adults provided the accompanying data (in dollars):
a
b
с
d
11
a
b
с
d
12
a
b
Given = 40.5% and n = 610 above, the fraction of sample proportions that fall within ±0.03 (3 percentage points) from
it is,
с
d
0.7841
0.8254
0.8688
0.9145
Given = 40.5% and n = 610 above, the lower and upper ends of the interval which captures 95 percent of all sample
proportions is,
0.389
0.383
0.376
0.366
1150
1006
1089
1163
936
835
1125
1002
929
1122
892
962
924
736
967
1003
The point estimate of population mean weekly wage is,
929.74
978.67
0.421
0.427
0.434
0.444
1030.18
1084.40
995.99
987.44
960
1045
1163
1052.06
1057.53
1064.37
1072.92
868
1261
1070
1147
1135
851
1368
1175
730
1240
1319
1193
1193
1101
1164
817
1247
810
1187
941
818
878
967
738
844
1218
978
963
957
The interval estimate for the population mean weekly wage with a 95% confidence level is,
1008.30
1002.83
1245
1146
965
1350
1073
1116
1519
733
1170
1042
974
748
766
923
830
873
1204
1117
1149
1490
879
982
865
827
You want to achieve a margin of error of $20 for the 95% confidence interval for the population weekly wage rate. What
is the minimum sample size to obtain this MOE?
For planning value use the standard deviation from original sample.
318
306
294
283
Suppose 280 students are taking E270. Each student is assigned to take a random sample of 100 workers in Indiana and
each build a 95% confidence interval for the average weekly wage.
How many of these 280 intervals should we expect to capture the actual population mean weekly wage.
95
275
270
266
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