d a breakup at least once during the last 10 years. Of nine randomly selected adults, find the probability that the number, X, who have years is m variable X. that you obtained in part (d) only approximately correct? What is the exact distribution called? ed a breakup at least once during the last 10 years is 0.109. s, inclusive, have experienced a breakup at least once during the last 10 years is 0.187. ability distribution of X. List the possible values of x in ascending order. 8 correct: 0

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**Probability and Statistics Practice Problem**

**Problem Statement:**

According to an article, 39% of adults have experienced a breakup at least once during the last 10 years. Suppose 9 adults are randomly selected, and the number of adults who have experienced a breakup at least once during the last 10 years is recorded.

1. **Let X represent the number of adults who have experienced a breakup at least once during the last 10 years. Explain why X is a binomial random variable.**
   
   X is a binomial random variable because:
   - There are a fixed number of trials (n = 9), which refers to the 9 adults selected.
   - Each trial has two possible outcomes: experiencing a breakup or not experiencing a breakup.
   - The probability of experiencing a breakup (success) is constant (p = 0.39).
   - The trials are independent, assuming that one adult’s experience does not influence another’s.

2. **Find the probability that at most one of the 9 adults experienced a breakup at least once during the last 10 years.**

   To solve this, we need to find the sum of the probabilities for X = 0 and X = 1 using the binomial probability formula:
   
   \[
   P(X = k) = \binom{n}{k} p^k (1 - p)^{n - k}
   \]
   
   Where:
   - \( n = 9 \)
   - \( p = 0.39 \)
   - \( k \) is the number of successes

   Calculate \( P(X = 0) \) and \( P(X = 1) \).

3. **Find the probability that at least one of the 9 adults experienced a breakup at least once during the last 10 years.**

   To find this, we need to determine:
   
   \[
   P(X \geq 1) = 1 - P(X = 0)
   \]
   
   Where \( P(X = 0) \) was found in the previous step.

4. **Complete the tables below to determine the probability distribution of X. List the possible values of X with their corresponding probabilities.**

   - **Table 1:** Probability Distribution
     
     | X | P(X = x) |
     |---|----------|
     | 0 |          |
     | 1 |          |
Transcribed Image Text:**Probability and Statistics Practice Problem** **Problem Statement:** According to an article, 39% of adults have experienced a breakup at least once during the last 10 years. Suppose 9 adults are randomly selected, and the number of adults who have experienced a breakup at least once during the last 10 years is recorded. 1. **Let X represent the number of adults who have experienced a breakup at least once during the last 10 years. Explain why X is a binomial random variable.** X is a binomial random variable because: - There are a fixed number of trials (n = 9), which refers to the 9 adults selected. - Each trial has two possible outcomes: experiencing a breakup or not experiencing a breakup. - The probability of experiencing a breakup (success) is constant (p = 0.39). - The trials are independent, assuming that one adult’s experience does not influence another’s. 2. **Find the probability that at most one of the 9 adults experienced a breakup at least once during the last 10 years.** To solve this, we need to find the sum of the probabilities for X = 0 and X = 1 using the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1 - p)^{n - k} \] Where: - \( n = 9 \) - \( p = 0.39 \) - \( k \) is the number of successes Calculate \( P(X = 0) \) and \( P(X = 1) \). 3. **Find the probability that at least one of the 9 adults experienced a breakup at least once during the last 10 years.** To find this, we need to determine: \[ P(X \geq 1) = 1 - P(X = 0) \] Where \( P(X = 0) \) was found in the previous step. 4. **Complete the tables below to determine the probability distribution of X. List the possible values of X with their corresponding probabilities.** - **Table 1:** Probability Distribution | X | P(X = x) | |---|----------| | 0 | | | 1 | |
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