(D² – 2D + 5)y = e* cos x

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I. Solve the given LDE using the method of undetermined coefficients.
(D² –3D+2)y =1+2x2 -e-x
2. (D² – 2D+ 5)y = e* cos x
3. (D² + D- 2)y = 2x – 40cos 2r
6. (D² +1)y = sin.x
7. (D³ - 6D²)y =3– cos x
8. (D° +4)y =-2; y(z /8) =1/2, y'(a / 8) = 2
9. (D² + 4D+ 5)y = 35e-x: y(0) = -3, y'(0) =1
10. y" - y' = 4e- +3e2x; y(0) = 0.y'(0) =-1.y"(0) = 2
1.
4. (D² - 3D)y = 8e3x + 4sinx
5. (D² +1)y = 2xsin x
Solve each of the following nonhomogeneous differential equations.
1. (D² +1)y= cscx
6. (D² -1)y= 2(1-e-2x)-1/2
2. (D² - 1)y -
7. (D² +1)y - cos²x
3. (D² - 3D +2)y=sine-*
1
8. (D² -1)y =
4. y"+y=sec³ xtanx
5. (D² -1)y = (1-e²*)-3/2
9. (D³ +D)y=sec²x
10. y" +y' = tanx
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A * TI 1) 11:58
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Transcribed Image Text:PowerPoint Presentation - qpdfview File Edit View Tabs Bookmarks Help 25 / 26 E → 83 % PowerPoint Presentation X PowerPoint Presentation 3 Activity Online work/Recitation/Homework I. Solve the given LDE using the method of undetermined coefficients. (D² –3D+2)y =1+2x2 -e-x 2. (D² – 2D+ 5)y = e* cos x 3. (D² + D- 2)y = 2x – 40cos 2r 6. (D² +1)y = sin.x 7. (D³ - 6D²)y =3– cos x 8. (D° +4)y =-2; y(z /8) =1/2, y'(a / 8) = 2 9. (D² + 4D+ 5)y = 35e-x: y(0) = -3, y'(0) =1 10. y" - y' = 4e- +3e2x; y(0) = 0.y'(0) =-1.y"(0) = 2 1. 4. (D² - 3D)y = 8e3x + 4sinx 5. (D² +1)y = 2xsin x Solve each of the following nonhomogeneous differential equations. 1. (D² +1)y= cscx 6. (D² -1)y= 2(1-e-2x)-1/2 2. (D² - 1)y - 7. (D² +1)y - cos²x 3. (D² - 3D +2)y=sine-* 1 8. (D² -1)y = 4. y"+y=sec³ xtanx 5. (D² -1)y = (1-e²*)-3/2 9. (D³ +D)y=sec²x 10. y" +y' = tanx O PowerPoint Presentati. [(3) Facebook - Mozill. A * TI 1) 11:58 pi
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