D 14 mm 300 mm| E B - 300 mm 3 mm 3 mm
Q: direct stress at A.
A:
Q: A thin rectangular plate is uniformly, deformed, as shown. Determine the shear strain Yxy at P.…
A: Solution: The shear strain of the thin rectangular sheet in the y-direction can be obtained using…
Q: The wood beam has an allowable shear stress of Tallow = 5 MPa. (Figure 1) Figure 50 mm 50 mm 50 mm…
A:
Q: When an axial load is applied to the ends of the bar shown in the figure, the total elongation of…
A: Given Elongation of the bar between A dan C δtotal = 0.22 in Strain ε2…
Q: Problem 2. From the given section of a wide flange shown in the figure, it carries a vertical shear…
A:
Q: The graph below shows the experimental stress - strain graphs for two materials, A and B. Identify…
A:
Q: A 8-mm-thick rectangular alloy bar is subjected to a tensile load P by pins at A and B, as shown in…
A:
Q: 10 lb 7 lb w=3lb/ft What is the value of the shear at point a? What is the value of the shear at…
A:
Q: the maximum compressive load a bone
A: Given: Outside radius is ro=2 cm Inside radius is ri=1.5 cm Maximum stress is σ=153 MPa Note: 1…
Q: Why R_[Ay) is calculated here? Explanation required
A: Step 1:Given data:A=6 mm2P=1.8 KNStep 2:Here A and B are left, right nail and RA,RB are reaction…
Q: The figure shows the stress versus strain plot for an aluminum wire that is stretched by a machine…
A:
Q: A force is applied to a circular surface with area 70 cm². The surface is parallel to the x-y plane.…
A:
Q: Poisson’s ratio for lead is 0.41. What change in volume takes place when a cube of lead of volume…
A: The given values are, σ=0.41V=1.0 dm3=1.0 dm30.1 m1 dm3=1.0×10-3 m3∆LL=2.0%=2.0100=0.02
Q: A 7-kip · ft torque is applied to a hollow aluminum shaft having the cross section shown. Neglecting…
A: Given data- T=7 kip-ft Radius of outer circle, r0=7 in Radius of inner circle, ri=14 in-4 in-2 in2=4…
If the following plate is subjected to deformation as shown by the dashed lines, determine the followings:
a- a- The average normal strain along the diagonal AC
b- b- The average shear strain in rad at the middle point E with respect to the x and y axes.
Step by step
Solved in 3 steps with 2 images
- Determine (a) the shear stress in the rivets and (b) the thickness "t" of the steel plate if the allowable bearing stress between the rivets and the plates is 110 MPa. 5-12 mm Ø 50 KN200 mm -50 KN 50 KN # +50 KNThe figure shows an approximate plot of stress versus strain for a spider-web thread, out to the point of breaking at a strain of 2.20. The vertical axis scale is set by a = 0.160 GN/m²,b = 0.500 GN/m?, and c = 0.720 GN/m². Assume that the thread has an initial length of 0.700 cm, an initial cross-sectional area of 7.00 × 10-12 m², and (during stretching) a constant volume. The strain on the thread is the ratio of the change in the thread's length to that initial length, and the stress on the thread is the ratio of the collision force to that initial cross-sectional area. Assume also that when the single thread snares a flying insect, the insect's kinetic energy is transferred to the stretching of the thread. (a) How much kinetic energy would put the thread on the verge of breaking? What is the kinetic energy of (b) a fruit fly of mass 5.50 mg and speed 2.20 m/s and (c) a bumble bee of mass 0.440 g and speed 0.840 m/s? Would (d) the fruit fly and (e) the bumble bee break the thread?…A sculpture weighing 10,000 N rests on a horizontal surface at the top of a 6.0-m-tall vertical pillar, see Figure below. The pillar's cross-sectional area is 0.20 m2 and it is made of granite with a mass density of 2700 kg/m3.Find the compressive stress at the cross-section located 3.0 m below the top of the pillar and the value of the compressive strain of the top 3.0-m segment of the pillar. *
- show complete solutionAn axial load Pis applied to the rectangular bar shown. The cross-sectional area of the bar is 216 mm?. Determine the normal stress perpendicular to plane AB and the shear stress parallel to plane AB if the bar is subjected to an axial load of P = 77 kN. Assume a = 61°. B Answers: The normal stress o = i MPа. The shear stresS T = MPa.The rubber blocks shown are used in a double U shear mount to isolate the vibration of a machine from its supports. An applied load of P = 336 N causes the upper frame to be deflected downward by 5.5 mm. Determine the shear modulus Gof the rubber blocks. Assume a = 10 mm, b = 22 mm, and c = 27 mm. Double U anti-vibration shear mount b P Rubber block dimensions Shear deformation of blocks Answer: Shear Modulus G = i MPa.
- · What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 1.9 × 104 mm and a crack length of 3.8 × 10-2 mm when a tensile stress of 140 MPa is applied?The strain components εx, εy, and γxy are given for a point in a body subjected to plane strain. Determine the principal strains, the maximum in-plane shear strain, and the absolute maximum shear strain at the point. Show the angle θp, the principal strain deformations, and the maximum in-plane shear strain distortion on a sketch. εx = -750 με, εy = -345 με, and γxy = 1250 μrad. Enter the angle such that -45°≤θp≤ +45°.The problem involves Strain energy concept. Please if you are not sure skip it , Don't give random answer.
- The 530-lb load is applied along the centroidal axis of the member. (Figure 1) PART A) Determine the magnitude of the resultant internal normal force in the member section b-b.Express your answer to three significant figures and include the appropriate units. PART B) Determine the magnitude of the resultant internal shear force in the member section b-b.Express your answer to three significant figures and include the appropriate units.Q2- A biological tissue underwent tensile tests, subjected to the axial load P. a) Determine the average normal (ơ) and average shear stresses (t) acting over area section shown below(A'), which is oriented at angle 0 from the horizontal, as a function of 0 and vertical cross section A. b) Determine angle 0 where o=3 t. (24 points) A'=A/sin0 P 01 A (Results: o =- (sine)²,t = - sin0 cose,0 = 71.56°) %3D A АHelp me please!