cyclopentane (C7H14) is in equilibrium with a vapour in a closed container. The vapour pressures of pure C6H12 and C7H14 are 389.32 mmHg and 108.56 mmHg, respectively. Vapour pressure of a pure substance is related to temperature by the Antoine equation (Equation A2a): Log10 p*= A - B/(T+C) Where p* is vapour pressure in mmHg, T is temperature in degrees Celsius, and A, B and C are constants given in Table A2a. Substance A B C cyclohexane (C6H₁2) 6.8413 1201.531 222.647 cyclopentane (C7H₁4) 6.8539 1331.57 216.36
cyclopentane (C7H14) is in equilibrium with a vapour in a closed container. The vapour pressures of pure C6H12 and C7H14 are 389.32 mmHg and 108.56 mmHg, respectively. Vapour pressure of a pure substance is related to temperature by the Antoine equation (Equation A2a): Log10 p*= A - B/(T+C) Where p* is vapour pressure in mmHg, T is temperature in degrees Celsius, and A, B and C are constants given in Table A2a. Substance A B C cyclohexane (C6H₁2) 6.8413 1201.531 222.647 cyclopentane (C7H₁4) 6.8539 1331.57 216.36
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
PART B ONLY PLEASE
![A2
A liquid mixture containing 6 moles of cyclohexane (C6H₁2) and 6 moles of
cyclopentane (C7H₁4) is in equilibrium with a vapour in a closed container. The
vapour pressures of pure C6H₁2 and C7H14 are 389.32 mmHg and 108.56 mmHg,
respectively. Vapour pressure of a pure substance is related to temperature by the
Antoine equation (Equation A2a):
Log10 p*= A - B/(T+C)
Where p* is vapour pressure in mmHg, T is temperature in degrees Celsius, and A, B
and C are constants given in Table A2a.
Substance
A
B
C
cyclohexane (C6H12)
6.8413 1201.531
6.8539 1331.57
222.647
216.36
cyclopentane (C7H14)
a. Determine the temperature of the system in Kelvin (K)
b. Using Raoult's Law and Dalton's Law, demonstrate that the total pressure in the
container is 248.94 mmHg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe525bdb2-53e9-4ee9-b678-8d9a068fe341%2F956d4607-b373-49e6-b4c3-aff57c3d9354%2F2raer86_processed.png&w=3840&q=75)
Transcribed Image Text:A2
A liquid mixture containing 6 moles of cyclohexane (C6H₁2) and 6 moles of
cyclopentane (C7H₁4) is in equilibrium with a vapour in a closed container. The
vapour pressures of pure C6H₁2 and C7H14 are 389.32 mmHg and 108.56 mmHg,
respectively. Vapour pressure of a pure substance is related to temperature by the
Antoine equation (Equation A2a):
Log10 p*= A - B/(T+C)
Where p* is vapour pressure in mmHg, T is temperature in degrees Celsius, and A, B
and C are constants given in Table A2a.
Substance
A
B
C
cyclohexane (C6H12)
6.8413 1201.531
6.8539 1331.57
222.647
216.36
cyclopentane (C7H14)
a. Determine the temperature of the system in Kelvin (K)
b. Using Raoult's Law and Dalton's Law, demonstrate that the total pressure in the
container is 248.94 mmHg
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