Cyclohexyne (A) is more stable than cyclohexane (B) becauseall atoms can adopt their ideal geometries.O TrueO False

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Answered: Cyclohexyne (A) is more stable than…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter7: Molecular Structures

Section: Chapter Questions

Problem 26QRT

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The concept of valence-shell electron-pair repulsion (VSEPR) is presented in introductory organic chemistry as a way to predict molecular geometries. The idea be- hind VSEPR is that areas of electron density repel each other so that the geometry of bonds and/or lone pairs of electrons around any one atom places these areas as far apart as possible. For four areas of electron density, a tetrahedral geometry is predicted. For three areas of electron density, a trigonal planar geometry is predicted. Two areas of electron density lead to a linear geometry. VSEPR is simply a predictive tool, but in some cases, it gives an incorrect prediction. In these instances, additional insights into bonding are necessary, such as resonance. Interestingly, several important situations are critical to biochemistry where VSEPR breaks down. Two examples are shown here. :O: CH3 H,N H3N CH3 H :0: :0: Histidine The circled nitrogen atoms are predicted by VSEPR to be tetrahedral in geometry because each…
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1. (A) Provide an example for each of the following: (a) a molecule that only has dispersion forces as IMFs (b) a molecule that has dispersion and dipolar IMFs (c) a molecule that can experience hydrogen bonding (B) Why does NH3 have a higher boiling point than BH3? To answer this question, draw out the Lewis structure for each molecule, and then draw out the VSEPR shape for each molecule.

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Cyclohexyne (A) is more stable than cyclohexane (B) because all atoms can adopt their ideal geometries. True False