Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the hydrocarbon product of the following reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. HO H3C. CH3 CH3 Q

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Chapter1: Chemical Foundations
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**Title**: Understanding Electron Flow in Organic Reactions

**Description**:

This educational illustration demonstrates the use of curved arrows to depict electron flow in a chemical reaction. 

**Instructions**:

- **Curved Arrows**: 
  - **First Arrow**: Indicates the movement of a lone pair of electrons from the hydroxide ion (HO⁻) to the hydrogen atom (H) attached to the carbon adjacent to the positively charged nitrogen (N⁺).
  - **Second Arrow**: Shows the electrons in the carbon-hydrogen bond moving to form a double bond between the alpha (α) carbon and the beta (β) carbon adjacent to the benzene ring.
  - **Third Arrow**: Represents the bond between the β carbon and the positively charged nitrogen breaking, with the electrons moving towards the nitrogen to neutralize the charge.

**Reaction Participants**:

- **N, N-Dimethylbenzylamine Ion**: The reaction starts from a quaternary ammonium ion, where the nitrogen is bonded to two methyl groups (CH₃), a benzyl group, and carries a positive charge (N⁺).
- **Hydroxide Ion (HO⁻)**: Acts as a base, initiating the deprotonation of the α-carbon hydrogen atom.

**Outcome**:

- **Product**: The final hydrocarbon product features a double bond between the α and β carbons, forming an alkene. Include lone pairs on the nitrogen after losing the methyl group. Ignore any inorganic byproducts.

This diagram emphasizes the role of electron movement in determining the progression and products of organic reactions, vital for understanding reaction mechanisms.
Transcribed Image Text:**Title**: Understanding Electron Flow in Organic Reactions **Description**: This educational illustration demonstrates the use of curved arrows to depict electron flow in a chemical reaction. **Instructions**: - **Curved Arrows**: - **First Arrow**: Indicates the movement of a lone pair of electrons from the hydroxide ion (HO⁻) to the hydrogen atom (H) attached to the carbon adjacent to the positively charged nitrogen (N⁺). - **Second Arrow**: Shows the electrons in the carbon-hydrogen bond moving to form a double bond between the alpha (α) carbon and the beta (β) carbon adjacent to the benzene ring. - **Third Arrow**: Represents the bond between the β carbon and the positively charged nitrogen breaking, with the electrons moving towards the nitrogen to neutralize the charge. **Reaction Participants**: - **N, N-Dimethylbenzylamine Ion**: The reaction starts from a quaternary ammonium ion, where the nitrogen is bonded to two methyl groups (CH₃), a benzyl group, and carries a positive charge (N⁺). - **Hydroxide Ion (HO⁻)**: Acts as a base, initiating the deprotonation of the α-carbon hydrogen atom. **Outcome**: - **Product**: The final hydrocarbon product features a double bond between the α and β carbons, forming an alkene. Include lone pairs on the nitrogen after losing the methyl group. Ignore any inorganic byproducts. This diagram emphasizes the role of electron movement in determining the progression and products of organic reactions, vital for understanding reaction mechanisms.
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