Curve Coordinate calculation If the PC is at N. 5000.00 E. 5000.00 and the direction from the PT to the PI is N 33-33-50W. What are the coordinates of the following point. 1+00 if the PC is located at 0+00. The curve has a radius of 1320.25 and Deflection angle of 12-45-30

Q: The equation station at the PT is:

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Q: Given a simple circular curve, in feet, with the following known information: o | = 45°20'15" o Da =…

A: Radius of the curve is given by below formula ; R = 5729.58Da Where ; Da = 5°00'00'' R =…

Q: Provide your COMPLETE solution, including illustrations and sketches, legibly. The bearings of…

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Q: What is the station of the PT of a horizontal curve with the following data: A=40°50', R=600 ft and…

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Q: The station of the Pl of a horizontal curve is 60+20. The horizontal curve will have a curve degree…

A: Given,PI = 60 + 20Degree of curve, D = 4oLength, L = 400 ft

Q: 1. a horizontal circular curve to the right contains an arc length of 1000ft and a central angle of…

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Q: A horizontal curve is being designed with tangent length of 850 ft and central angle of 0.7315…

A: The given data is: The equation applied to determine the central angle : radius, usually measured to…

Q: 1. You are traversing along a centerline, (S 45° 00' E), at Station 1+50, you establish a BC, for a…

A: To Determine Length T1 and T2 of the given compound curve.

Q: The bearing of a back tangent of a simple curve is N 65°00' E, while the forward tangent has a…

A:

Q: A -1.10% grade meets a +0.60% grade at station 36+00 and elevation 800.00 ft. The +0.60 grade then…

A: Grade, g1 = +2.40Grade, g2 = +0.60Elevation = 800.00 ft

Q: A compound circular curve has: R₁ = 500m, R₂ = 750m, A₁ = 38° 20', A₂ = 41° 30′ St. P.I = (28+50)…

A: Given: Compound circular curve R1 = 500m, R2 = 750 m  Sta. PI = (28+50) Co-ordinates of PI (E = 500,…

Q: Horizontal highway curve: Given Pl at 10 + 71.78, A = 36°10'30", and R = 1,150 ft, compute the…

A: Given Radius 1150 ftAngle 36°10`30``To find out Deflections

Q: Compute the radius of horizontal circular curve if you know the station of PC (25+24.23) and station…

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Q: 24.9 Highway curve with Da = 5°00', I = 20°30' and PI station 63 +25.53 ft. =

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Q: The bearing of a back tangent of a simple curve is N 65°00' E, while the forward tangent has a…

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Q: Q5: given the following information: A= 16° 38' R = 1000 m PI at 6+26.57 Calculate the station of…

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Q: %3D A horizontal curve has a radius of 980.80 ft.; an I = 23°00'00"; and, PC Station = 76+68.50 ft.…

A: Deflection angle∆: Length of curve L = πR∆180 R is the radius of curve  R=980.8 ft ∆ is the…

Q: The bearing of a back tangent of a simple curve is N 65°00' E, while the forward tangent has a…

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Q: The azimuth of the tangents of the simple curve is 505 degrees and 776 degrees respectively. The…

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