Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The chemical equation given is:
\[ \text{Cu} + 2\text{AgNO}_3 \rightarrow \text{Cu(NO}_3\text{)}_2 + 2\text{Ag} \]
**Question:**
8.80 moles of \(\text{AgNO}_3\) react with how many moles of \(\text{Cu}\)?
**Options:**
- 4.80 mol
- 3.40 mol
- 6.80 mol
- 13.6 mol
**Explanation:**
In this reaction, 2 moles of \(\text{AgNO}_3\) react with 1 mole of \(\text{Cu}\). Therefore, to determine how many moles of \(\text{Cu}\) react with 8.80 moles of \(\text{AgNO}_3\), we use the stoichiometric ratio from the balanced equation:
\[ \frac{1 \text{ mol of Cu}}{2 \text{ mol of AgNO}_3} = x \text{ moles of Cu} / 8.80 \text{ mol of AgNO}_3 \]
Solving for \(x\):
\[ x = \frac{1}{2} \times 8.80 \]
\[ x = 4.40 \text{ mol} \]
Since 4.40 mol is not an option, ensure that the answer is accurate in the context of the original question's details or re-evaluate the given options.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35844c14-8e0f-4ef2-9129-409849687b45%2F58b45317-56e4-44c0-b80c-fab4e0459c8c%2Fl9ofjid_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The chemical equation given is:
\[ \text{Cu} + 2\text{AgNO}_3 \rightarrow \text{Cu(NO}_3\text{)}_2 + 2\text{Ag} \]
**Question:**
8.80 moles of \(\text{AgNO}_3\) react with how many moles of \(\text{Cu}\)?
**Options:**
- 4.80 mol
- 3.40 mol
- 6.80 mol
- 13.6 mol
**Explanation:**
In this reaction, 2 moles of \(\text{AgNO}_3\) react with 1 mole of \(\text{Cu}\). Therefore, to determine how many moles of \(\text{Cu}\) react with 8.80 moles of \(\text{AgNO}_3\), we use the stoichiometric ratio from the balanced equation:
\[ \frac{1 \text{ mol of Cu}}{2 \text{ mol of AgNO}_3} = x \text{ moles of Cu} / 8.80 \text{ mol of AgNO}_3 \]
Solving for \(x\):
\[ x = \frac{1}{2} \times 8.80 \]
\[ x = 4.40 \text{ mol} \]
Since 4.40 mol is not an option, ensure that the answer is accurate in the context of the original question's details or re-evaluate the given options.
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