Credit Score0-15Number of Applicants 7015-30 30-45254545-60 60-75 75-90 90+30 23 10 0Perform a goodness of fit test at the 5% significance level of the null hypothesisthat the observed credit scores follow an Exponential distribution.

The null and Alternative hypothesis are:- Ho : The observed credit scores follow an Exponential…

Answered: Credit Score 0-15 15-30 Number of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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0 - no 1 - yes By hand find the 95% agresti confidence interval for the difference in proportions of athlete and non athlete where the two groups are defined as in state or out of state. Interpret the results.
uppose the price per share of stock for a sample of 25 companies was recorded at the beginning of the first financial quarter and then again at the end of the first financial quarter. How stocks perform during the first financial quarter is an indicator of what is ahead for the stock market and the economy. Company End of 1st quarter Beginning of 1st quarter Company 1 54.69 55.32 Company 2 56.20 78.52 Company 3 103.07 110.50 Company 4 80.45 85.08 Company 5 126.51 140.73 Company 6 133.23 137.28 Company 7 32.56 42.57 Company 8 51.41 54.54 Company 9 35.90 37.94 Company 10 14.55 19.48 Company 11 33.04 40.04 Company 12 45.33 40.36 Company 13 185.13 189.53 Company 14 109.28 109.45 Company 15 72.46 92.15 Company 16 49.32 55.03 Company 17 36.70 43.73 Company 18 79.57 86.18 Company 19 95.50 87.45 Company 20 43.09 47.09 Company 21 51.32 66.70 Company 22 77.45 86.53 Company 23 46.77 45.99 Company 24 46.45 48.13 Company 25 130.36 129.08 (a)…
Treatment Sham Researchers conducted a study to determine whether magnets are effective in treating back pain. The results are shown in the table for the treatment (with magnets) group and the sham (or placebo) group. The results are a measure of reduction in back pain. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard H1 H2 23 23 deviations are equal. Complete parts (a) and (b) below. 0.57 0.39 0.62 1.29 a. Use a 0.05 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment. What are the null and alternative hypotheses? O A. Ho: H1 =H2 O B. Ho: H1 H2 H1: H1
Using ANOVA example on body temperature for different age groups, test whether these programmers commit same number of errors on average. State Ho vs Ha Test statistic
Tourists watched caribou groups to determine what activities the caribou groups do at certain times of the day. A two-way table summarizing the data is provided in the table below. Does the data provide enough evidence to show that there is an association between activity and time of day? Test at the 8% level and round expected values to one decimal place. Activity Morning (Observed) Morning (Expected Value) Afternoon(Observed) Afternoon (Expected Value) Row Total Travel 52 46 98 Feed 52 12 64 Social 74 34 108 Column Total 178 92 270
State the hypothesis in terms of expected proportions
com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IQirVmXK7o_zpyaAMkjWKJh-pmWc8lyVwdR5jMFrpEk1OKo2aqYNpEXQ2W4CqM9coDe - Arts and Sc... Wabbitemu TI Calc... Mail - Jones, Rashe... O CONIPIDENCE INTERVALS AND HYPOTHESIS TESTNG Hypothesis test for a population proportion Ras A hospital claims that the proportion, P, of full-term babies born in their hospital that weigh more than / pounds is 46%, In a random sample of 155 babies born in this hospital, 56 weighed over / pounds. Is there enough evidence to reject the hospital's claim at the 0.1 level of significance? Perform a two-tailed test. Then fill in the table below. Carry termediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) The null hypothesis: The alternative hypothesis: The type of test statistiL: Choose onel v 曲 The value ot the test statistic: (Round to at least three decimal places) decimal ciace) Can se reeL the dei at treprartion of fu…
K Are you an impulse shopper? A survey of 800 grocery shoppers indicated that 18% of males and 50% of females make an impulse purchase every time they shop. Assume that the survey consisted of 400 males and 400 females. Complete parts (a) and (b) below. search State the conclusion.. the null hypothesis. There is evidence at the 0.05 level of significance to conclude that there is a difference in the proportion of males and females who make an impulse purchase every time they shop. b. Find the p-value in (a) and interpret its meaning. The p-value is (Round to three decimal places as needed.). Interpret the p-value. The p-value is the probability that in a random sample of 800 adults, the difference between the proportions of males and females who make an impulse purchase the difference in this sample, assuming that the proportion of males who make an impulse purchase every time every time they shop will be the proportion for females in the population. they shop is #1 I C 86°F VSIA 441
Runs Test If we use a 0.05 significance level to test for randomness, what are the critical values from Table A-10? Based on those values and the number of runs from Exercise 2, what should be concluded about randomness?
Single-Sample z test. Here are the Degree of Reading Power (DRP) scores for a random sample of 10 third grade students in the Albany City school district: 31, 27, 38, 34, 42, 28, 26, 43, 46, 27 You wonder whether the mean score of this sample is greater than the population mean of all third grade students in the Albany City school district, which is 30. Suppose scores on the DRP are known to be normally distributed with a population standard deviation of 11. Step 1) Population 1 (Sample): Population 2: Null Hypothesis (H0): Research Hypothesis (H1): Step 2) Determine the characteristics of the comparison distribution. Sample Mean = M = _________ Mean of the population = μ = ________ Population standard deviation = = _________ Standard deviation of distribution of means = = __________ Step 3) Determine the cutoff score on the z distribution (use a 0.05 p value). Cut-off score = _________ Step 4) Determine your sample’s z score. z = ___________ Step…
TRUE OR FALSE
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Credit Score 0-15 15-30 Number of Applicants 70 45 30-45 45-60 60-75 75-90 90+ 25 30 23 10 0 Perform a goodness of fit test at the 5% significance level of the null hypothesis that the observed credit scores follow an Exponential distribution.