Create the binary tree with 9 nodes by using pointer-based representation. struct TreeNode { int info; TreeNode * left; TreeNode * right; }
Create the binary tree with 9 nodes by using pointer-based representation. struct TreeNode { int info; TreeNode * left; TreeNode * right; }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Please implement the followings:
1. Create the binary tree with 9 nodes by using pointer-based representation. struct TreeNode { int info; TreeNode * left; TreeNode * right; }
2. Implement pre-order, in-order, and post-order traversals, and print the results of the tree (Figure 1). 2 7 5 2 6 9 5 11 4
(Figure 1 and question in image below). Please help.
![Please implement the followings:
1. Create the binary tree with 9 nodes (Figure 1) by using pointer-based representation.
struct TreeNode
{
int info;
TreeNode * left;
TreeNode * right;
}
2. Implement pre-order, in-order, and post-order traversals, and print the results of the tree
(Figure 1).
2
7
5
2
6
9
5
(11
4
Figure 1
Sample Run:
Part 1
The pre-order transversal looks like this:
The in-order transversal looks like this:
The post-order transversal looks like this:
2
7
2
6
5
11
5
9
4
2
7
5
6
11
2
5
4
9
2
5
11 6
7
4
9
5 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F620c60a1-10fe-416e-8b85-1e75a34b227e%2F7cc5e0b3-9ca1-4117-9d60-2ca06d79eb02%2Fs30je39_processed.png&w=3840&q=75)
Transcribed Image Text:Please implement the followings:
1. Create the binary tree with 9 nodes (Figure 1) by using pointer-based representation.
struct TreeNode
{
int info;
TreeNode * left;
TreeNode * right;
}
2. Implement pre-order, in-order, and post-order traversals, and print the results of the tree
(Figure 1).
2
7
5
2
6
9
5
(11
4
Figure 1
Sample Run:
Part 1
The pre-order transversal looks like this:
The in-order transversal looks like this:
The post-order transversal looks like this:
2
7
2
6
5
11
5
9
4
2
7
5
6
11
2
5
4
9
2
5
11 6
7
4
9
5 2
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