Create a method called calcArea.  It will calculate and return the area of the triangle using this formula:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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PYTHON!!

class Triangle:
    
    def __init__(self,sides):
        
        self.a = sides[0]
        self.b = sides[1]
        self.c = sides[2]

if __name__ == '__main__':
   
    t = Triangle([3,6,2])
    
    print(f'Side1 = {t.a}')
    print(f'Side2 = {t.b}')
    print(f'Side3 = {t.c}')

Based on the code.  Assume you are in the Triangle class:

Create a method called calcArea

It will calculate and return the area of the triangle using this formula: 

The image displays Heron's formula for calculating the area of a triangle when the lengths of all three sides are known.

**Formula:**
\[ \text{area} = \sqrt{s(s - a)(s - b)(s - c)} \]

**Where:**
\[ s = \frac{1}{2}(a + b + c) \]

- \( a \), \( b \), and \( c \) are the lengths of the sides of the triangle.
- \( s \) is the semi-perimeter of the triangle.

The formula involves taking the square root of a product. First, calculate the semi-perimeter \( s \) by adding the side lengths \( a \), \( b \), and \( c \), then dividing by 2. Next, substitute these values into Heron's formula to find the area.
Transcribed Image Text:The image displays Heron's formula for calculating the area of a triangle when the lengths of all three sides are known. **Formula:** \[ \text{area} = \sqrt{s(s - a)(s - b)(s - c)} \] **Where:** \[ s = \frac{1}{2}(a + b + c) \] - \( a \), \( b \), and \( c \) are the lengths of the sides of the triangle. - \( s \) is the semi-perimeter of the triangle. The formula involves taking the square root of a product. First, calculate the semi-perimeter \( s \) by adding the side lengths \( a \), \( b \), and \( c \), then dividing by 2. Next, substitute these values into Heron's formula to find the area.
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