courseld=17388460&OpenVellumHMAC=91a79942 Part5 A study finds that the carapace length of an adult spider is normally distributed with a mean of 14.27 mm and a stane the adult spider. U. (Z-14.27) X= 1.25 (Z-1.25) 14.27 c. Identify and sketch the distribution of z. Choose the correct graph below. OA. OB. Q -2 1 4 11 12 14.27 17 18 d. Find the z-scores that correspond to the percentage of adult spiders that have carapace lengths between 12 mm a The percentage of adult spiders that have carapace lengths between 12 mm and 13 mm is equal to the area under t (Round to two decimal places as needed.) e. Find the z-score and direction that corresponds to the percentage of adult spiders that have carapace lengths exce The percentage of adult spiders that have carapace lengths exceeding 15 mm is equal to the area under the standar- (Round to two decimal places as needed.) Q Q X=

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### Understanding Normal Distribution through an Example of Adult Spider Carapace Lengths

A study finds that the carapace length of an adult spider is normally distributed with the following parameters:
- Mean (µ): 14.27 mm
- Standard Deviation (σ): 1.25 mm

Let \( x \) denote carapace length for an adult spider.

To understand the distribution and specific characteristics of this dataset, several statistical analyses and representations can be performed.

#### a. Identify and Sketch the Distribution of Z
To comprehend the distribution, you need to identify the correct graphical representation. The options provided are typically for understanding the shape and spread of a normal distribution.

(Graph options are usually labeled as A, B, C, etc., which represent possible shapes of the normal distribution curve).

#### b. Z-Scores Corresponding to Specific Percentages
1. **Percentage of Adult Spiders with Carapace Lengths between 12 mm and 13 mm**

   To find the percentage of carapace lengths between 12 mm and 13 mm, calculate the Z-scores for these values and then find the corresponding area under the standard normal curve:
   - Z-score for x = 12 mm: 
     \[
     Z = \frac{12 - 14.27}{1.25} \approx -1.82
     \]
   - Z-score for x = 13 mm:
     \[
     Z = \frac{13 - 14.27}{1.25} \approx -1.02
     \]

   (These need to be rounded to two decimal places.)

#### c. Percentage of Carapace Lengths Exceeding 15 mm

   To find the percentage of adult spiders with carapace lengths exceeding 15 mm:
   - Calculate the Z-score for 15 mm:
     \[
     Z = \frac{15 - 14.27}{1.25} \approx 0.58
     \]

   This Z-score can be converted to a percentage by finding the area to the right of this value under the standard normal distribution curve.

### Visual Representation and Details
Accompanying these calculations are graphs that illustrate the normal distribution curve, the area corresponding to certain Z-scores, and the specific intervals.

- **Graph A**: Typically depicts a standard normal distribution.
- **Graph B**: Focuses on smaller region or specific plot representation.
- **Graph
Transcribed Image Text:### Understanding Normal Distribution through an Example of Adult Spider Carapace Lengths A study finds that the carapace length of an adult spider is normally distributed with the following parameters: - Mean (µ): 14.27 mm - Standard Deviation (σ): 1.25 mm Let \( x \) denote carapace length for an adult spider. To understand the distribution and specific characteristics of this dataset, several statistical analyses and representations can be performed. #### a. Identify and Sketch the Distribution of Z To comprehend the distribution, you need to identify the correct graphical representation. The options provided are typically for understanding the shape and spread of a normal distribution. (Graph options are usually labeled as A, B, C, etc., which represent possible shapes of the normal distribution curve). #### b. Z-Scores Corresponding to Specific Percentages 1. **Percentage of Adult Spiders with Carapace Lengths between 12 mm and 13 mm** To find the percentage of carapace lengths between 12 mm and 13 mm, calculate the Z-scores for these values and then find the corresponding area under the standard normal curve: - Z-score for x = 12 mm: \[ Z = \frac{12 - 14.27}{1.25} \approx -1.82 \] - Z-score for x = 13 mm: \[ Z = \frac{13 - 14.27}{1.25} \approx -1.02 \] (These need to be rounded to two decimal places.) #### c. Percentage of Carapace Lengths Exceeding 15 mm To find the percentage of adult spiders with carapace lengths exceeding 15 mm: - Calculate the Z-score for 15 mm: \[ Z = \frac{15 - 14.27}{1.25} \approx 0.58 \] This Z-score can be converted to a percentage by finding the area to the right of this value under the standard normal distribution curve. ### Visual Representation and Details Accompanying these calculations are graphs that illustrate the normal distribution curve, the area corresponding to certain Z-scores, and the specific intervals. - **Graph A**: Typically depicts a standard normal distribution. - **Graph B**: Focuses on smaller region or specific plot representation. - **Graph
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