​ country's tax collection agency reported that 82​% of individual tax returns were filed electronically in 2017. A random sample of 236 tax returns from 2018 was selected. From this​ sample, 185 were filed electronically. Complete parts a through c. a. Construct a 95​% confidence interval to estimate the actual proportion of taxpayers who filed electronically in 2018.

Q: A 93.32% Cl is given as (2.5, 3.5). From this information, find a 95% confidence interval (yes, this…

A: The provided information is as follows:The 93.32% confidence interval is (2.5,3.5).

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: A poll reported that 67.7% of adults in a certain country believe that organic produce is better for…

A:

Q: In a survey of 2726 adults, 1497 say they have started paying bills online in the last year.…

A: Find z-critical value:…

Q: CareerBuilder took a random sample of 1,600 workers and found that 592 of them would put in their…

A: given data sample size (n) =1600favorable outcomes (x) = 59290% ci p.

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: Construct a 99.8% confidence interval for the proportion of women who work at home who are college…

A: Given,n=519x=165p^=xnp^=165519=0.318The point estimation for the proportion is 0.318 .

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: Suppose a random sample of 142 graduates admissions officers were asked what role scores on…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: T.J. wants to estimate the percentage of college students who have taken out student loans. He…

A:

Q: sample of 35 students was taken from the local university. These students spent an average of $180…

A:

Q: A history teacher records the SAT scores of all 87 of her students. The data is used to construct a…

A: For calculating the confidence interval, we need to satisfy the following conditions: Independence…

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: The random variable cyber bullied follows normal distribution. The sample size is 14795. The number…

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Givenx=722n=1762p^=7221762p^=0.4098α=1-0.98=0.02α2=0.01zc=z0.01=2.3263         (from z-table)

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: In a survey of 2311​ adults, 716 say they believe in UFOs.   Construct a 95% confidence interval for…

A: Solution: Let X be the number of adults say they believe in UFOs and n be the sample number of…

Q: own residents were interviewed and it was found that 422 responded favorably to a question while 501…

A: given data, 422-favorably responded501-negetively responded 923- total  interviewed for positive…

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: In a sample of 310 adults, 177 had children. Construct a 87% confidence interval for the true…

A: Find z-critical value:…

Q: A recent study indicated that 24% of women over 55 are widows. A researcher wishes to estimate with…

A:

Q: ed 1294 people whether they performed any volunteer work during the past year. A total of 517 people…

A: The sample proportion is computed as follows,

Q: In a survey, 64% said they are most likely to sleep and 18% said they watch television. Although…

A:

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: Suppose that 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: The sample proportion is given as 0.18. The sample size is given as 2307. The two-tailed z-critical…

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: A country's tax collection agency reported that 82% of individual tax returns were filed…

A: From the provided information,Confidence level = 95%

Q: Find the margin of​ error, using a​ 95% confidence​ level, for estimating the percentage of all…

A: Given:- simple random sample of 1200 young people  so, n= 1200 86% had earned a high school diploma…

Q: A magazine publisher wishes to determine what proportion of current subscribes will renew. The…

A: we have given that  sample size n=200 and favorable cases x=108  sample proportion p^= x/n =108/200…

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…