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95% confidence interval for the true percent of workers in this city who have full health insurance coverage. Express your results to the nearest hundredth of a percent. Your answer should be expressed as a percentage in the form XX.XX Answer: to %

95% confidence interval for the true percent of workers in this city who have full health insurance coverage. Express your results to the nearest hundredth of a percent. Your answer should be expressed as a percentage in the form XX.XX Answer: to %

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A random sample of 1700 workers in a particular city found 544 workers who had full health insurance coverage. Find a 

**Text:** 95% confidence interval for the true percent of workers in this city who have full health insurance coverage. **Express your results to the nearest hundredth of a percent. Your answer should be expressed as a percentage in the form XX.XX** **Answer:** [Input Box] **to** [Input Box] % **Explanation:** This text is a prompt for calculating a 95% confidence interval for the proportion of workers with full health insurance coverage. The result should be presented as a percentage rounded to the nearest hundredth, expressed in the form XX.XX. Two input boxes are provided for entering the lower and upper bounds of the confidence interval, which signify the range within which the true percentage is expected to lie with 95% confidence.
Transcribed Image Text:**Text:** 95% confidence interval for the true percent of workers in this city who have full health insurance coverage. **Express your results to the nearest hundredth of a percent. Your answer should be expressed as a percentage in the form XX.XX** **Answer:** [Input Box] **to** [Input Box] % **Explanation:** This text is a prompt for calculating a 95% confidence interval for the proportion of workers with full health insurance coverage. The result should be presented as a percentage rounded to the nearest hundredth, expressed in the form XX.XX. Two input boxes are provided for entering the lower and upper bounds of the confidence interval, which signify the range within which the true percentage is expected to lie with 95% confidence.
Expert Solution
Step 1: Determine the given variables.

The question is about confidence interval.

Given :

Randomly selected no. of workers ( n ) = 1700

No. of workers among "n" who had full health insurance coverage ( x ) = 544

Confidence level ( C ) = 0.95


To find :

95% confidence interval for the true % of workers in the city who have full health insurance coverage.

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