Counting available electrons and Drawing a Lewis Structure: Count the total number of valence electrons in a molecule. This is just the sum of the number of valence electrons from each atom in the molecule. An easy way to determine the valence electrons is to look at the group number on the periodic table. For this worksheet, we abbreviate the total number of valence electrons as, ae, which stands for available electrons. Determine the value of ae for each molecule. Example: SICI, ae Si=4 ae =32 4- Cl = 4*7 = 28 | Total = 32 PCI, ae = de = SF. ae = For polyatomic ions the number of valence electrons is calculated in the same way as above but we must add electrons if the ion has a negative charge or subtract electrons for a positive charge. For example: SO- S= 6 40= 4* 6 = 24 -2 charge = 2 = 34 ae = 34 total NH, ae = ae = XeFs* CH. in the space to the right connect all of the atoms to the ac = Trial Structure: central atom and then make each atom follow the octet rule (duet rule for hydrogen).

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Counting available electrons and drawing a Lewis structures

Counting available electrons and Drawing a Lewis Structure:
Count the total number of valence electrons in a molecule. This is just the sum of
the number of valence electrons from each atom in the molecule.
An easy way to determine the valence electrons is to look at the group
number on the periodic table.
For this worksheet, we abbreviate the total number of valence electrons as, ae,
which stands for available electrons.
Determine the value of ae for each molecule.
Example: SiCl,
ae
Si=4
4- Cl = 4*7 = 28
Total = 32
PCI3
ae =32
de =
ae =
SF.
ae =
C2Ha
For polyatomic ions the number of valence electrons is calculated in the same way
as above but we must add electrons if the ion has a negative charge or subtract
electrons for a positive charge. For example:
S= 6
40 = 4* 6 = 24
-2 charge = 2
total
ae = 34
= 34
ae =
NH,
ae =
XeFs*
CH4
in the space to the
right connect all of
ae =
Trial Structure:
the atoms to the
central atom and
then make each
atom follow the
octet rule (duet rule
for hydrogen).
Transcribed Image Text:Counting available electrons and Drawing a Lewis Structure: Count the total number of valence electrons in a molecule. This is just the sum of the number of valence electrons from each atom in the molecule. An easy way to determine the valence electrons is to look at the group number on the periodic table. For this worksheet, we abbreviate the total number of valence electrons as, ae, which stands for available electrons. Determine the value of ae for each molecule. Example: SiCl, ae Si=4 4- Cl = 4*7 = 28 Total = 32 PCI3 ae =32 de = ae = SF. ae = C2Ha For polyatomic ions the number of valence electrons is calculated in the same way as above but we must add electrons if the ion has a negative charge or subtract electrons for a positive charge. For example: S= 6 40 = 4* 6 = 24 -2 charge = 2 total ae = 34 = 34 ae = NH, ae = XeFs* CH4 in the space to the right connect all of ae = Trial Structure: the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen).
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