Counting available electrons and Drawing a Lewis Structure: Count the total number of valence electrons in a molecule. This is just the sum of the number of valence electrons from each atom in the molecule. An easy way to determine the valence electrons is to look at the group number on the periodic table. For this worksheet, we abbreviate the total number of valence electrons as, ae, which stands for available electrons. Determine the value of ae for each molecule. Example: SICI, ae Si=4 ae =32 4- Cl = 4*7 = 28 | Total = 32 PCI, ae = de = SF. ae = For polyatomic ions the number of valence electrons is calculated in the same way as above but we must add electrons if the ion has a negative charge or subtract electrons for a positive charge. For example: SO- S= 6 40= 4* 6 = 24 -2 charge = 2 = 34 ae = 34 total NH, ae = ae = XeFs* CH. in the space to the right connect all of the atoms to the ac = Trial Structure: central atom and then make each atom follow the octet rule (duet rule for hydrogen).
Counting available electrons and Drawing a Lewis Structure: Count the total number of valence electrons in a molecule. This is just the sum of the number of valence electrons from each atom in the molecule. An easy way to determine the valence electrons is to look at the group number on the periodic table. For this worksheet, we abbreviate the total number of valence electrons as, ae, which stands for available electrons. Determine the value of ae for each molecule. Example: SICI, ae Si=4 ae =32 4- Cl = 4*7 = 28 | Total = 32 PCI, ae = de = SF. ae = For polyatomic ions the number of valence electrons is calculated in the same way as above but we must add electrons if the ion has a negative charge or subtract electrons for a positive charge. For example: SO- S= 6 40= 4* 6 = 24 -2 charge = 2 = 34 ae = 34 total NH, ae = ae = XeFs* CH. in the space to the right connect all of the atoms to the ac = Trial Structure: central atom and then make each atom follow the octet rule (duet rule for hydrogen).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Counting available electrons and drawing a Lewis structures
![Counting available electrons and Drawing a Lewis Structure:
Count the total number of valence electrons in a molecule. This is just the sum of
the number of valence electrons from each atom in the molecule.
An easy way to determine the valence electrons is to look at the group
number on the periodic table.
For this worksheet, we abbreviate the total number of valence electrons as, ae,
which stands for available electrons.
Determine the value of ae for each molecule.
Example: SiCl,
ae
Si=4
4- Cl = 4*7 = 28
Total = 32
PCI3
ae =32
de =
ae =
SF.
ae =
C2Ha
For polyatomic ions the number of valence electrons is calculated in the same way
as above but we must add electrons if the ion has a negative charge or subtract
electrons for a positive charge. For example:
S= 6
40 = 4* 6 = 24
-2 charge = 2
total
ae = 34
= 34
ae =
NH,
ae =
XeFs*
CH4
in the space to the
right connect all of
ae =
Trial Structure:
the atoms to the
central atom and
then make each
atom follow the
octet rule (duet rule
for hydrogen).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F921f6546-af39-43f1-aaa9-36572b00cf90%2Fc4d31544-2755-469d-af55-d2ee328760c3%2Fc2jn0r8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Counting available electrons and Drawing a Lewis Structure:
Count the total number of valence electrons in a molecule. This is just the sum of
the number of valence electrons from each atom in the molecule.
An easy way to determine the valence electrons is to look at the group
number on the periodic table.
For this worksheet, we abbreviate the total number of valence electrons as, ae,
which stands for available electrons.
Determine the value of ae for each molecule.
Example: SiCl,
ae
Si=4
4- Cl = 4*7 = 28
Total = 32
PCI3
ae =32
de =
ae =
SF.
ae =
C2Ha
For polyatomic ions the number of valence electrons is calculated in the same way
as above but we must add electrons if the ion has a negative charge or subtract
electrons for a positive charge. For example:
S= 6
40 = 4* 6 = 24
-2 charge = 2
total
ae = 34
= 34
ae =
NH,
ae =
XeFs*
CH4
in the space to the
right connect all of
ae =
Trial Structure:
the atoms to the
central atom and
then make each
atom follow the
octet rule (duet rule
for hydrogen).
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Recommended textbooks for you
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
![Principles of Instrumental Analysis](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
![Chemistry](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
![Principles of Instrumental Analysis](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
![Organic Chemistry](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
![Chemistry: Principles and Reactions](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
![Elementary Principles of Chemical Processes, Bind…](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY