Count the divisions double fct (const double A[], int n) { } if (n == 0 ) return 1 else return (A [n-1]/A [n-1])/fct (A, n-1);
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![Count the divisions
double fct (const double A[], int n)
{
}
if (n ==
0 )
return 1
else
return (A [n-1]/A [n-1])/fct (A, n-1);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1027cba2-85fd-4401-a389-5e49baac07e3%2F10df6fae-d235-45a6-8dd3-314a4c06c77f%2F09s5bm_processed.jpeg&w=3840&q=75)
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- Recursive Count Write a recursive function rc_count(L:List[int], x:int) -> int that takes a list L and an integer x. The function returns the number of occurrences of x in L. For example, rc_count([1,1,2,3], 1) returns 2 and rc_count([1,1,2,3], 4) returns 0. Your Answer: 1 # Put your answer here 2 Submitin C programing Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b,4) should return 0.int isSorted(int *array, int n){int g(int nums[], int n) { if (n == 1) return 0; int val = g(nums, n-1); if (nums[n-1] > nums[val]) return val; return n-1; } Give a recurrence T(n) for the number of times the code nums[n-1] > nums[val] is executed when the array values are in ascending order. Then solve the recurrence
- 11 - The code segment below has time complexity? for (int i=0; iGiven an integer array of positive single digit values such as:int a[] = {8,4,2,6,9};1) Write a recursive arrayToN function which returns the concatenation of all array values as an integer value.This function should accept all required data as parameters and return a long integer value.ExamplesIf the array is 8 4 2 6 9 the arrayToN function returns the integer 84269.If the array is 0 2 6 8 9 3 5 1 the arrayToN function returns the integer 2689351.Sorting Design and Analysis For this assignment, you need to study the performance of 2 designed algorithms using different logic. You need to write a program in C language that takes N (size of input) then write the following functions/methods: int[] GenerateValues (N) where N is random int values between 0 and N-1. DistinctValues Algorithms: int findDistintValuesWithoutSort( A, N) to count the number of distinct values in A without sorting algorithm. int findDistintValuesWithSort( A, N) to count the number of distinct values using any sorting algorithm (i.e., quicksort or merge sort or heapsort). Print the execution time for each method to find the distinct values where N = 103, 104, and 105. Note the execution time in a table and discuss your results in the document file. Discuss the execution time compared to your big -O analysis of the 2 DistinctValues algorithms.int X[900]; int Y[600]; int sum, sum1, sum2, sum3; //parallelism : dividing outer loop in three parts //i = 1 to 300 for(i=1;i<=300;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 301 to 600 for(i=301;i<=600;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 601 to 900 for(i=601;i<=900;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } sum = sum1 + sum2 + sum3;} another way to solve the question that send in the picWrite the implementations of functionscopy1 and copy2 for copying strings. copy1 uses array index notation. copy2 uses Pointers andPointer Arithmetic.#include <stdio.h>#define SIZE 10void copy1(char* s1, const char* s2); // prototypevoid copy2(char* s1, const char* s2); // prototypeint main(void){char string1[SIZE]; // create array string1char *string2 = "Hello"; // create a pointer to a stringcopy1(string1, string2);printf("string1 = %s\n", string1);char string3[SIZE]; // create array string3char string4[] = "Good Bye"; // create an array containing a stringcopy2(string3, string4);printf("string3 = %s\n", string3);}void copy1(char* s1, const char* s2){//Implement copying string using array index notation}void copy2(char* s1, const char* s2){//Implement copying string using Pointers and Pointer Arithmetic }void func(vector<string>& names){ sort(names.begin(), names.end()); //(a) for(int i = names.size() - 1; i > 0; --i){. //(b) if(names[i] == names[i - 1]){ names[i] = move(names.back()); names.pop_back(); } } } What are the reasons or consequences for the programmer’s choice to loop backwards in the line marked (b), and under what circumstances would the algorithm behave differently if that line were replaced with: for (int i = 1; i < names.size(); ++i) ? What would change?#include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…import java.lang.System; 3. public class FibonacciComparison { 4. // Fibonacci Sequence: 0, 1, 1, 2, 3, 5, 8 .... /* 7 input cases 8. 1) 0 9 2) 3 10 3) -1 11 4) 9 12 output cases 13 1) 0 14 2) 2 15 3) 0 16 4) 34 17 */ // Note that you need to return 0 if the input is negative. // Please pay close attention to the fact that the first index in our fib sequence is 0. 18 19 20 // Recursive Fibonacci public static int fib(int n) { // Code this func. 21 22 23 24 return -1; 25 26 // Iterative Fibonacci 27 28 public static int fiblinear(int n) { // Code this func. 29 30 return -1; 31 32 33 public static void main(String[] args) { 34 // list of fibonacci sequence numbers int[] nlist w { 5,10, 15, 20, 25, 30, 35, 40, 45}; 35 36 37 // Two arrays (one for fibLinear, other for fibRecursive) to store time for each run. // There are a total of nlist.length inputs that we will test double[] timingsEF = new double[nlist.Length]; double[] timingsLF = new double[nlist.length]; 38 39 40 41 42 // Every…SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. 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