Could you please explain the difference between Incomplete Penetrance, Incomplete Dominance, and Variabale Expressivity? I can't keep them separate.
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A:
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A: The above image belongs to the ferns. It is the prothallus of the fern developed from spores.
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Q: What is Dominance variance ?
A: Variations are the genetic features present in the organisms distinct from their parents.
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Q: what is incomplete dominance? give examples. use F1 and F2 punnet squares.
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A: Answer: MONOHYBRID CROSS : It is the cross between one trait of two types of an indivdual.
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A: Sir Gregor Mendel was a priest and a teacher who did the famous hybridization experiment on garden…
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Could you please explain the difference between Incomplete Penetrance, Incomplete Dominance, and Variabale Expressivity? I can't keep them separate.
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- I'm confused about how I would figure out these two questions as I don't really understand the difference or where to start. What are the observed genotypic frequencies for Wildrose at the pt-8 locus? and What are the observed allelic frequencies for Wildrose at the pt-8 locus?I don't really understand how to solve this question. For part a, I think my approach would be to find the genotypes of the parents first, and find the genotype of the F1. For part B, I would like to get some clarifications on the difference between linked genes with no crossing over vs. unlinked genes when approaching Punnett square type questions. Thank you also answer part a and bX-linked recessive, carrier mother Unaffected. Carrier mother father X Y XX |Unaffected |Affected I Carrier XY Unaffected Unaffected Carrier daughter Affected son daughter U.S. National Library of Medicine son Color blindedness is a sex-linked trait. If we could see the pedigree chart for several more generations of the family illustrated here, we would expect A) more males to be color blind. B) móre females to be color blind. no females to ever be color blind. D) an equal number of males and females that are color blind.
- Consider the following pedigree. 하 3 10 (5 3 2 (a) What pattern of transmission is most consistent with this pedigree? (1) autosomal recessive, (2) autosomal dominant, (3) X-linked recessive, (4) X-linked dominant. (b) If individual V-2 marries a normal individual, and if the condition has a pene-trance of 85 percent, what is the probability that their second child will express the trait? (c) On the third line, what does the diamond with a 10 in the middle mean?To play Jeopardy, the answer is given. You must supply the question. Choose the best question for the following answer: Mutant allele causing malfunction of the wild-type allele, giving rise to a dominant phenotype. What is codominance? What is incomplete dominance? O What is dominant negative? O What is haploinsufficiency?I will be adding two questions here because I asked two of the same questions twice by accident earlier. A man and a woman do not have hemophilioa, but the womans father did. (Hemophilia is X-linked recessive). a) What is the probability that they will have a child with hemophilia? b) Is it possible for any of their daughters to be affected? Explain. A cross between a horse homozygous for red hair and a horse homozygous for white hair results in offspring with the coat colour called roan. When you look at the fur of the roan offspring you see both red and white hairs. What type of inheritance best explains this? a) blending inheritance b)codominance c)incomplete codominance d)multiple alleles
- A young couple went to see a genetic counselor because each had a sibling with cystic fibrosis. (Cystic fibrosis is a recessive disease, and neither member of the couple nor any of their four parents is affected.) What is the probability that the female of this couple is a carrier? What are the chances that their child will have cystic fibrosis? 3. What is the probability that their child will be a carrier of the cystic fibrosis disease allele?in this image How many different phenotypic categories do you observe in the resulting progeny? Which phenotype(s) is/are different between these categories?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?There are six types of agglutinogen named C,D, E and c,d,e.the first three are dominant and last three are recessive.discuss
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