Could you please explain step by step how the answer in the example highlighted in yellow was deduced? I am not sure how it was obtained. I attached two screen shots as one is the beginning of the problem and the other is the second part that is highlighted that is where I am confused.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Could you please explain step by step how the answer in the example highlighted in yellow was deduced? I am not sure how it was obtained. I attached two screen shots as one is the beginning of the problem and the other is the second part that is highlighted that is where I am confused.

) – Vx– (1
Example 5
Find an equation of the tangent line to the curve at
y = Vx/(1 + x²) the point (1, ).
2-1
Solution:
2x2
According to the Quotient Rule, we have
25
d
(1 + x²) – (/x) – VI
dy
(1 + x²)
dx
dx
dx
(1 + x²)²
1
(1 + x²)
2 Vx
(1 + x²)?
VI (2x)
|
Transcribed Image Text:) – Vx– (1 Example 5 Find an equation of the tangent line to the curve at y = Vx/(1 + x²) the point (1, ). 2-1 Solution: 2x2 According to the Quotient Rule, we have 25 d (1 + x²) – (/x) – VI dy (1 + x²) dx dx dx (1 + x²)² 1 (1 + x²) 2 Vx (1 + x²)? VI (2x) |
Example 5 – Solution
cont'd
(1 + x²) – 4x²
2 Vx (1 + x²)²
1 – 3x²
x(1 + x²)²
.2
|
So the slope of the tangent line at (1, 2) is
1 – 3 · 1²
2 Vī(1 + 1²)²,
2
dy
-
%3D
dx
x=1
Transcribed Image Text:Example 5 – Solution cont'd (1 + x²) – 4x² 2 Vx (1 + x²)² 1 – 3x² x(1 + x²)² .2 | So the slope of the tangent line at (1, 2) is 1 – 3 · 1² 2 Vī(1 + 1²)², 2 dy - %3D dx x=1
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