Could you please elaborate on the highlighted part, it goes too fast for me , please show it step by step , how do they suddenly get s2k?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Could you please elaborate on the highlighted part, it goes too fast for me , please show it step by step , how do they suddenly get s2k?

Lemma 14.11 Let Sn =
integer n.
Proof
n
k=1
= 1+
1
1
n
+-, where ne N. Then S2 ≥1+ for every positive
2
n
We proceed by induction. For n = 1, $₂¹ = 1 + and so the result holds for n = 1.
1
2
k
, where ke N. We show that S₂k+1 ≥ 1+
Assume that s₂k ≥ 1+
that
2
$2k+1 = 1+
1
2
= $₂k +
≥ S₂k +
= S₂k +
+
1
2k + 1
1
2k+1
2k
2k+1
1
2k+1
1
2k +2
1
2k+1
+
+
+
S2k +
k 1
≥1+=+ =1+
2 2
+
1
+
2
k + 1
2
+
1
2k+1
1
ok+1
By the Principle of Mathematical Induction, S2″ ≥1+
integer n.
n
IN
k+1
2
Now observe
for every positive
Transcribed Image Text:Lemma 14.11 Let Sn = integer n. Proof n k=1 = 1+ 1 1 n +-, where ne N. Then S2 ≥1+ for every positive 2 n We proceed by induction. For n = 1, $₂¹ = 1 + and so the result holds for n = 1. 1 2 k , where ke N. We show that S₂k+1 ≥ 1+ Assume that s₂k ≥ 1+ that 2 $2k+1 = 1+ 1 2 = $₂k + ≥ S₂k + = S₂k + + 1 2k + 1 1 2k+1 2k 2k+1 1 2k+1 1 2k +2 1 2k+1 + + + S2k + k 1 ≥1+=+ =1+ 2 2 + 1 + 2 k + 1 2 + 1 2k+1 1 ok+1 By the Principle of Mathematical Induction, S2″ ≥1+ integer n. n IN k+1 2 Now observe for every positive
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