could u please explain how is the final equation gotten. What is Vex and how are the equations for Vout and Vex obtained. When are the signs negative and positive. Hope u can do a step by step explantion with illustrations. Thank you in advance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. ■ Rearrange R₂ The differential buffer amplifier provides high input impedance (i.e., You it does not load the bridge) and high gain for the small change in voltage due to the small change in resistance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. Vout= i₁R₁-i₂R₂ = -i₁R₁+1₂R₂ V = i,(R₁ + R₂) = i₂(R₂ + R₂) ex R₂ Vout = V₁R₁+R₂ R₂ + R
could u please explain how is the final equation gotten. What is Vex and how are the equations for Vout and Vex obtained. When are the signs negative and positive. Hope u can do a step by step explantion with illustrations. Thank you in advance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. ■ Rearrange R₂ The differential buffer amplifier provides high input impedance (i.e., You it does not load the bridge) and high gain for the small change in voltage due to the small change in resistance. differential buffer amplifier Figure 9.23 Dynamic unbalanced bridge circuit. Vout= i₁R₁-i₂R₂ = -i₁R₁+1₂R₂ V = i,(R₁ + R₂) = i₂(R₂ + R₂) ex R₂ Vout = V₁R₁+R₂ R₂ + R
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Plz solve this problem within 20 minutes I have to submit it within 25 minutes will definitely voteup thanks ? ? ?
![could u please explain how is the final equation
gotten. What is Vex and how are the equations
for Vout and Vex obtained. When are the signs
negative and positive. Hope u can do a step by
step explantion with illustrations. Thank you in
advance.
Ve
Rearrange
Figure 9.23 Dynamic unbalanced bridge circuit.
Figure 9.23 Dynamic unbalanced bridge circuit.
Vout= i₁R₁-1₂R₂ = -1₁R₁+1₂R₂
Vex i₁(R₁ + R₂) = ₂(R₂ + R₂)
R₁
R₁ + R₁
V
out
= V
The differential buffer
amplifier provides
high
input impedance (i.e.,
-out it does not load the
differential
buffer
amplifier
differential
bufier
R₂
R₂ + R
bridge) and high gain
for the small change
in voltage due to the
small change in
resistance.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd53c981-d3fb-4d86-b451-2d7f878ea24b%2F8b656295-642b-4239-9da8-3bc8cae776bc%2Fo01h3uo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:could u please explain how is the final equation
gotten. What is Vex and how are the equations
for Vout and Vex obtained. When are the signs
negative and positive. Hope u can do a step by
step explantion with illustrations. Thank you in
advance.
Ve
Rearrange
Figure 9.23 Dynamic unbalanced bridge circuit.
Figure 9.23 Dynamic unbalanced bridge circuit.
Vout= i₁R₁-1₂R₂ = -1₁R₁+1₂R₂
Vex i₁(R₁ + R₂) = ₂(R₂ + R₂)
R₁
R₁ + R₁
V
out
= V
The differential buffer
amplifier provides
high
input impedance (i.e.,
-out it does not load the
differential
buffer
amplifier
differential
bufier
R₂
R₂ + R
bridge) and high gain
for the small change
in voltage due to the
small change in
resistance.
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