I need the answer as soon as possible cos(0.60,.6How did he get the valueinside the red circle(c)27n T 00-2r.eQ = Pudv72 sin 0 drdedør.20 0.01 + 1)(2]2r-cos 01%[Ø]"2.[2][27] 6.28C

Following integral formula will bw usful for solving given integral Integration (eax)= eax/a…

Answered: cos(0.60 .6 How did he get the value…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Refer to the National Electrical Code® or the working drawings when necessary. Where applicable, responses should be written in complete sentences. For problems 1 and 2, six luminaires, similar to Style E used in the Commercial Building, are to be installed in a room that is 12 ft x 18 ft (~3.7 m x ~5.5 m) with a 9 ft (2.8 m) floor-to-ceiling height. The spacing ratio for the luminaire is 1:0. 1. The maximum distance that the luminaires can be separated and achieve uniform illuminance is ft ( m). For problems 2-5, two luminaires, 8 ft (2.5 m) and 4 ft (1.2 m) in length with dimensions as shown in Figure 15-7, are to be installed in tandem (end to end). The end of the long luminaire is to be 2 ft (600 mm) from the wall. 2. The center of the outlet box should be roughed in at ft ( m) from the wall. 3. The first support should be installed at the wall. ft ( m) from 4. The second support should be installed at from the wall. ft ( m) 5. The final support should be installed at the wall. ft…
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cos(0.60 .6 How did he get the value inside the red circle (c) 27n T 0 2r r? sin 0 drdedø .2 0 0.0 cos 015(0)8" = + e [1 + 1][27] 2r Q =0+(2](27) = 6.28C