cos 2xdx CoS Vsin2x

Q: secx cos )

A:

Q: 1. (xy' – y) cos ( 2у COS -3x4

A: Since you have asked multiple questions, we will answer the first question. If you need answer for…

Q: ∫cos^3 xdx

A: Given: ∫cos3xdx

Q: y = ce2x cos 3x + c2e2x sin 3x

A: By Bartleby policy I have to solve only first one as these are all unrelated & lengthy…

Q: cos52xdx cos$2x

A: Given- ∫cos52xcos82xdx To Find- The value of the integral.

Q: csc (tan 2y-1)dy 5. cos* 2y wil

A: topic - indefinite integral

Q: | cos 3xdx=

A: The given integral is ∫cos3x dx. Let u=3x. Then du=3 dx.

Q: Evaluate (3x + cos 4x) dx

A:

Q: S(sinx – cosx)²dx COoSx

A: Given, ∫sinx-cosx2dx  We have to find the integral.

Q: cos 4z - cos 2z =

A: cosx−cosy​=−2sinx+y2sinx−y​2​

Q: = Vx* – - 4 cos x+/7x %3D

A:

Q: Find y' and y". y=2sin4x-cos(8x-1)

A: Let's find.

Q: Cosx=0.42

A:

Q: cos2x Evaluate dx sin²2x- 16 12

A: This definite integral is based on the substitution method.

Q: COS 7t 6

A:

Q: 2z2 cos 5z dz EVALUATE.

A:

Q: (15t-2 – 5t) cos (6t-1+t²)

A: using substitution method to find integration

Q: V3 11. cos(3x) = %3D

A: cosθ   is negative in 2nd and 3rd quadrant

Q: y=cos(4x) /cos22x-4sin2x cos2x differentiate?

A:

Q: ブーーコニメCos(2x 2.

A:

Q: B) Find f cos5 x dx C) Find f cos2sin2 x dx

A:

Q: y = 2e cosx

A:

Q: Cos %3D 6.

A: To find the value of trigonometric function

Q: cos (x) 2 %3D X = Submit

A:

Q: cos (2x)

A:

Q: (3-2)* V | (2r2 – 1) cos 3rdr | Cos

A:

Q: 4sinx •cotx / cos2x + 1

A: You know:

Q: 7- y" + ²y = cos 2t, ²4; y(0) = 1, y'(0) = 0

A:

Q: +2 y = 3e" cos 2x -2

A: Solution

Q: Cos t csct

A: cos t csc t

Q: cos( + B) = O V2(cosB + V3sinB) V3(cosB - V2sinB) O V2(cosB - V3sinB)

A: Value of Cos(π/3 + B) will be

Q: If y = sinx + cosx, then y" is - sinx + COSSX sinx - cosx COSX O sinx - coSX O sinx + coSx

A:

Q: 3) y(³) − y(¹) = cos(2x). —

A:

Q: coS 3dv

A: on solving this we get

Q: | sin2xdx = %3D cos2x A O +C cos2x B O +C 2 cos2x+CCO -2 cos2x+CDO

A: ∫sin(2x)dx= -(cos2x)/2+C

Q: Cos 0 do |3| 3 6. 0.

A: ∫06πcosθdθ    = sinθ06π    = sin6π-sin0    = 0 - 0   = 0

Q: y = cos((TX)5)

A: Please see the white board.

Q: (cos(3x)(/1 – c os(5æ))dæ -

A: Use the formula 2cosA sinB = sin(A+B)-sin(A-B)

Q: 3x*y+2x +y² +5 = cos(2x)+5x

A:

Q: cos2x

A:

Q: CoS 2n du.

A:

Q: tan xdx cos 2x-7

A: To find the integration.

Q: COS X+ 3sin 2X

A: It is given that y''+y=cosx+3sin2x. We have to find the general solution of the given…

Q: 2 Sinx Cose - Cosx eE 2/CoS 3% t Cas ex

A: I am attaching image so that you understand each and every step.

Q: Evaluate: cos³x dx sinx I =

A: We know that : sin2x + cos2x =1. we know that integration of xn = xn+1/ n+1 We use all of  this to…

Q: fa cos (6x) cos (3x)dx

A:

Q: Integrate  cos3xcos2x

A:

Q: Differentiate: y = 2 cos² (x² + 2) %3D

A: Given that, y=2cos2(x2+2)

Q: Evaluate ∫ex cos3(ex) dx using tables after performing the substitution u = ex.

A: We have to evaluate the integral by substitution method: ∫ex cos3ex dx Substituting, u=ex…