Then we get a1D+a2d + azD+ a4d+ azd aid+ a2D+ azd+ a4D+ azD D = AD+ and d= Ad+ B1D+ B2d + B3D+ Bad + Bzd Bid + B2D+ B3d+ B4D+ Bs D' or (a1 + a3) D+ (a2 + a4 + a5) d (B1 + B3) D + (B2 + B4 + Bs) d (a1+ a3) d+ (a2 + a4 + a5) D (B1 + B3) d+ (B2 + B4 + B5) D D (1 – A) = and d(1– A) : From which we have (a1 + a3) D + (a2 + a4 + as)d-(1 – A) (81 + B3) D² = (1 – A) (32 + B4 + B3) Dd (5.41) and (a1 + a3) d+ (a2 +a4 + a5) D-(1 – A) (31 + B3) ď² = (1 - A) (32 + B4 + B5) Dd (5.42) From (5.41) and (5.42), we obtain (d - D) {[(a1 + a3) – (a2 + a4 + az3)] – (1 – A) (B1 + B3) (d + D)} = 0. (5.43)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Topic Video
Question

Explain the determine red and the inf is here

The main focus of this article is to discuss some qualitative behavior of
the solutions of the nonlinear difference equation
a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5
Ym+1 =
Aym+
т 3D 0, 1, 2, ...,
В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5
(1.1)
Transcribed Image Text:The main focus of this article is to discuss some qualitative behavior of the solutions of the nonlinear difference equation a1Ym-1+ a2Ym-2 + a3Ym-3 + a4Ym-4+ a5Ym-5 Ym+1 = Aym+ т 3D 0, 1, 2, ..., В1ут-1 + В2ут-2 + Взут-3 + Влут-4 + B5ут-5 (1.1)
Case 4. Let the function H(uo, ..., u5) is non-decreasing in uo,u1,u3 and
non-increasing in u2, u4, U5.
Suppose that (d, D) is a solution of the system
D =
H(D,D,d, D, d, d)
and
d = H(d, d, D, d, D, D).
Then we get
a1D+a2d + a3D+a4d + azd
a1d + a2D + azd + a4D + a5D
D = AD+
and d= Ad+
B1D+ B2d + B3D+ B4d + Bzd
Bid + B2D+ B3d + B4D+ B5D’
or
(a1 + a3) D+ (a2 + a4 + a5) d
(B1 + B3) D + (B2 + B4 + B5) d
(a1 + a3) d + (a2+ a4 + az) D
(B1 + B3) d + (82 + B4 + B5) D
D(1 – A) =
and d(1– A) =
-
From which we have
+ a3) D+ (a2 + a4 + az) d-(1 – A) (B1 + B3) D² = (1 – A) (B2 + B4 + B5) Dd
(5.41)
and
(a1 + a3) d+ (a2 + a4 + a5) D-(1 – A) (B1 + B3) ď² = (1 – A) (82 + B4 + B5) Dd
(5.42)
From (5.41) and (5.42), we obtain
(d – D) {[(a1 + a3) – (a2 + a4 + a5)] – (1 – A) (B1 + B3) (d + D)} = 0.
(5.43)
Since A < 1 and (a2 + a4 + a5) > (a1 + a3), we deduce from (5.43) that
D = d. It follows by Theorem 2, that ỹ of Eq.(1.1) is a global attractor.
It follows by Theorem 2, that ỹ of Eq.(1.1) is a global attractor and the
proof is now completed.
Transcribed Image Text:Case 4. Let the function H(uo, ..., u5) is non-decreasing in uo,u1,u3 and non-increasing in u2, u4, U5. Suppose that (d, D) is a solution of the system D = H(D,D,d, D, d, d) and d = H(d, d, D, d, D, D). Then we get a1D+a2d + a3D+a4d + azd a1d + a2D + azd + a4D + a5D D = AD+ and d= Ad+ B1D+ B2d + B3D+ B4d + Bzd Bid + B2D+ B3d + B4D+ B5D’ or (a1 + a3) D+ (a2 + a4 + a5) d (B1 + B3) D + (B2 + B4 + B5) d (a1 + a3) d + (a2+ a4 + az) D (B1 + B3) d + (82 + B4 + B5) D D(1 – A) = and d(1– A) = - From which we have + a3) D+ (a2 + a4 + az) d-(1 – A) (B1 + B3) D² = (1 – A) (B2 + B4 + B5) Dd (5.41) and (a1 + a3) d+ (a2 + a4 + a5) D-(1 – A) (B1 + B3) ď² = (1 – A) (82 + B4 + B5) Dd (5.42) From (5.41) and (5.42), we obtain (d – D) {[(a1 + a3) – (a2 + a4 + a5)] – (1 – A) (B1 + B3) (d + D)} = 0. (5.43) Since A < 1 and (a2 + a4 + a5) > (a1 + a3), we deduce from (5.43) that D = d. It follows by Theorem 2, that ỹ of Eq.(1.1) is a global attractor. It follows by Theorem 2, that ỹ of Eq.(1.1) is a global attractor and the proof is now completed.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Research Design Formulation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,