Then we get a1D+a2d + azD+ a4d+ azd aid+ a2D+ azd+ a4D+ azD D = AD+ and d= Ad+ B1D+ B2d + B3D+ Bad + Bzd Bid + B2D+ B3d+ B4D+ Bs D' or (a1 + a3) D+ (a2 + a4 + a5) d (B1 + B3) D + (B2 + B4 + Bs) d (a1+ a3) d+ (a2 + a4 + a5) D (B1 + B3) d+ (B2 + B4 + B5) D D (1 – A) = and d(1– A) : From which we have (a1 + a3) D + (a2 + a4 + as)d-(1 – A) (81 + B3) D² = (1 – A) (32 + B4 + B3) Dd (5.41) and (a1 + a3) d+ (a2 +a4 + a5) D-(1 – A) (31 + B3) ď² = (1 - A) (32 + B4 + B5) Dd (5.42) From (5.41) and (5.42), we obtain (d - D) {[(a1 + a3) – (a2 + a4 + az3)] – (1 – A) (B1 + B3) (d + D)} = 0. (5.43)
Then we get a1D+a2d + azD+ a4d+ azd aid+ a2D+ azd+ a4D+ azD D = AD+ and d= Ad+ B1D+ B2d + B3D+ Bad + Bzd Bid + B2D+ B3d+ B4D+ Bs D' or (a1 + a3) D+ (a2 + a4 + a5) d (B1 + B3) D + (B2 + B4 + Bs) d (a1+ a3) d+ (a2 + a4 + a5) D (B1 + B3) d+ (B2 + B4 + B5) D D (1 – A) = and d(1– A) : From which we have (a1 + a3) D + (a2 + a4 + as)d-(1 – A) (81 + B3) D² = (1 – A) (32 + B4 + B3) Dd (5.41) and (a1 + a3) d+ (a2 +a4 + a5) D-(1 – A) (31 + B3) ď² = (1 - A) (32 + B4 + B5) Dd (5.42) From (5.41) and (5.42), we obtain (d - D) {[(a1 + a3) – (a2 + a4 + az3)] – (1 – A) (B1 + B3) (d + D)} = 0. (5.43)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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