Correct each molecule in the drawing area below so that it has the condensed structure it would have if it were dissolved in a 0.1 M aqueous solution of HCl. If there are no changes to be made, check the No changes box under the drawing area. No changes. - CH₁₂ -C-H HO–CH,—CH, - -C-CH3 : G

CH3 OH CH3 111 CH3-CH-CH-CH-CH3 A P + H₂O Specifically, in the drawing area below draw the condensed structure of P. Click anywhere to draw the first atom of your structure. X

Correct each molecule in the drawing area below so that it has the condensed structure it would have if it were dissolved in a 0.1 M aqueous solution of HCl. If there are no changes to be made, check the No changes box under the drawing area. + ☑ CH₂- ·C. - CH, NH, CH3 C-OH :

I have given you a condensed structure. You need to convert it to an accurate bond-line structure. CH3 CH3-CH-CH2-CH-CH₂-C-H 12-CH-CH2₂-C-1 CI Draw (as bond-line structures) isomers of this compound where you only move the chlorine atom. Draw four isomers of the original compound that would have a five carbon chain as the longest chain. [Note: there would be many isomers that will satisfy this. Find any four.] Using the original molecule (and looking at the carbon next to the aldehyde carbonyl) what would be the charge on that carbon if I removed an H atom and left behind the pair of electrons? Circle the best answer Positive Negative Neutral In the space below, draw that structure (from the sentence above) as a bond-line structure. Then, draw a resonance structure for this ion and be sure to add curved arrows to show the movement of electrons.