coring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches. Use the References to access important values if needed for this question. Match each compound in the group on the left with the compound on the right most likely to have the same electrical conductivity per mole in aqueous olution. CH₂- CH₂ -CH₂ H₂N CH₂-CH₂ NH₂ Trimethylamine Ethylenediamine Ne

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches.
Use the References to access important values if needed for this question.
Match each compound in the group on the left with the compound on the right most likely to have the same electrical conductivity per mole in aqueous
solution.
CH₂
CH₂ CH₂ H₂N
Trimethylamine
NMe
CH₂-CH₂
NH₂
Ethylenediamine
en
Transcribed Image Text:Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches. Use the References to access important values if needed for this question. Match each compound in the group on the left with the compound on the right most likely to have the same electrical conductivity per mole in aqueous solution. CH₂ CH₂ CH₂ H₂N Trimethylamine NMe CH₂-CH₂ NH₂ Ethylenediamine en
CH3.
CH3-N CH3 H₂N
Trimethylamine
NMe3
Ethylenediamine
en
[Co(en)₂Br₂]Br
[V(bipy)3] Cl3
CH₂-CH₂
[Pt(en)3]Cl4
Li₂[CuCl4]
NH₂
[TiBr3(NMe3)3]
CH₂CH₂OH
KCI
BaClz
Fe(NO3)3
Al₂(SO4)3
Clear All
Transcribed Image Text:CH3. CH3-N CH3 H₂N Trimethylamine NMe3 Ethylenediamine en [Co(en)₂Br₂]Br [V(bipy)3] Cl3 CH₂-CH₂ [Pt(en)3]Cl4 Li₂[CuCl4] NH₂ [TiBr3(NMe3)3] CH₂CH₂OH KCI BaClz Fe(NO3)3 Al₂(SO4)3 Clear All
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