Copy the figure shown below onto your scratch paper. Na SCH, Box 1 NaO Box 2 Then, complete the figure on your scratch paper by drawing out the intermediates and arrow-pushing mechanism in Boxes 1-2 that explain the formation of the final products shown You should start your arrow-pushing in Box 1, and you will use all boxes Now, report the formal charges (+,0,-) that appear on the sulfur, bromine, and alpha carbon atoms in each box and match the contents of each box to a single phrase (A-G) that best describes the mechanistic step that occurs in each box A. A nucleophile attacks a tertiary carbocation B. A nucleophile attacks a secondary carbocation. C. A nucleophile attacks, and a leaving group leaves. D. Br is protonated, and S is deprotonated. E. A leaving group leaves F.S is protonated, and Br is deprotonated G. A carbocation attacks S. S formal charge (t,0.) Br formal charge (0,) Ca formal charge (0 Phrase (A.G) Box 1: Вох 2: Products: 0

Copy the figure shown below onto your scratch paper. Na SCH, Box 1 NaO Box 2 Then, complete the figure on your scratch paper by drawing out the intermediates and arrow-pushing mechanism in Boxes 1-2 that explain the formation of the final products shown You should start your arrow-pushing in Box 1, and you will use all boxes Now, report the formal charges (+,0,-) that appear on the sulfur, bromine, and alpha carbon atoms in each box and match the contents of each box to a single phrase (A-G) that best describes the mechanistic step that occurs in each box A. A nucleophile attacks a tertiary carbocation B. A nucleophile attacks a secondary carbocation. C. A nucleophile attacks, and a leaving group leaves. D. Br is protonated, and S is deprotonated. E. A leaving group leaves F.S is protonated, and Br is deprotonated G. A carbocation attacks S. S formal charge (t,0.) Br formal charge (0,) Ca formal charge (0 Phrase (A.G) Box 1: Вох 2: Products: 0

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Copy the figure shown below onto your scratch paper. Box 1 Box 2 Box 3 HBr Br -> Then, complete the figure on your scratch paper by drawing out the intermediates and arrow-pushing mechanism in Boxes 1-3 that explain the forrmation of the final products shown. You should start your arrow-pushing in Box 1, and you will use all boxes. Now, report the formal charges (+,0,-) that appear on Cy, Cy, and bromine atoms in each box, and match the contents of each box to a single phrase (A-H) that best describes the mechanistic step that occurs in each box. A. A hydride shift occurs. B. A methyl shift occurs. C. A nucleophile attacks a tertiary carbocation. D. A leaving group leaves. E. A nucleophile attacks a secondary carbocation. F. Br is protonated, Cy is deprotonated, and a pi bond forms G. A carbocation attacks the Br. H. Br is protonated, Cx is deprotonated, and a pi bond forms Cx formal charge (+,0,) Cy formal charge (±.0_) Br formal charge (+,0,-) Phrase (A-H) Box 1:0 Box 2: Вох 3:…
QUESTION 7 Copy the figure shown below onto your scratch paper. Box 1 Box 2 Box 3 HBr Br Then, complete the figure on your scratch paper by drawing out the intermediates and arrow-pushing mechanism in Boxes 1-3 that explain the formation of the final products shown. You should start your arrow-pushing in Box 1, and you will use all boxes. Now, report the formal charges (+,0,-) that appear on the alpha carbon, beta carbon, and bromine atoms in each box, and match the contents of each box to a single phrase (A-H) that best describes the mechanistic step that Occurs in each box. A. A hydride shift occurs. B. A methyl shift occurs. C. A nucleophile attacks a tertiary carbocation. D. A leaving group leaves. E. A nucleophile attacks a secondary carbocation. F. Br is protonated, the alpha carbon is deprotonated, and a pi bond forms G. A carbocation attacks the Br. H. Br is protonated, the beta carbon is deprotonated, and a pi bond forms Ca formal charge (+,0,-) CR formal charge (+,0,-) Br…
I dont get what I am doing wrong for the second product.
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