Convert the following from mg/L as Caco3 to mg/L as the ion or compounds. (*Answers in whole number only. No engineering expression like 10S, No unit) 100.00 mg/L S042 (a) mg/L 30.00 mg/L HCO3 (b) mg/L 150.00 mg/L Ca2* (c) mg/L 10.00 mg/L H2CO3 (d] mg/L 150.00 mg/L Na* (e] mg/L
Convert the following from mg/L as Caco3 to mg/L as the ion or compounds. (*Answers in whole number only. No engineering expression like 10S, No unit) 100.00 mg/L S042 (a) mg/L 30.00 mg/L HCO3 (b) mg/L 150.00 mg/L Ca2* (c) mg/L 10.00 mg/L H2CO3 (d] mg/L 150.00 mg/L Na* (e] mg/L
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Convert the following from mg/L as Caco3 to mg/L as the lon or compounds.
(*Answers in whole number only. No engineering expression like 10S, No unit)
100.00 mg/L SO42 (a] mg/L
30.00 mg/L HCO3 (b) mg/L
150.00 mg/L Ca2* [c] mg/L
10.00 mg/L H2CO3 [d] mg/L
150.00 mg/L Na* (e] mg/L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed218552-f604-4b26-b023-fb65bc476393%2F06c55dcf-406e-453e-a22c-e315207ae50a%2Frvxz9p6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Convert the following from mg/L as Caco3 to mg/L as the lon or compounds.
(*Answers in whole number only. No engineering expression like 10S, No unit)
100.00 mg/L SO42 (a] mg/L
30.00 mg/L HCO3 (b) mg/L
150.00 mg/L Ca2* [c] mg/L
10.00 mg/L H2CO3 [d] mg/L
150.00 mg/L Na* (e] mg/L
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